Answer: 0.421
Step-by-step explanation:
Heavy smoker = 20%
Light smoker = 30%
Non smokers = 50%
We can assume that the probability that a non-smoker is going to die in the next 5 years be y.
Since light smokers were twice as likely as nonsmokers to die during the five-year study, the probability will be:
= 2 × y = 2y
Probability for the Heavy smokers will be:= 2 × 2y = 4y
The expected number of people that will die for each in the next 5 years will be:
Non smoker:
= 50% × y
= 0.5 × y
= 0.5y
Light smoker:
= 30% × 2y
= 0.3 × 2y.
= 0.6y
Heavy smoker:
= 20% × 4y.
= 0.2 × 4y
= 0.8y
Total = 0.5y + 0.6y + 0.8y = 1.9y
The probability that the participant was a heavy smoker will be:
= 0.8y/1.9y
= 0.421
Answer:
The solution is (0, 3/4)
Step-by-step explanation:
Please copy and share the instructions. Here they are: Solve the following system of linear equations.
Both of the equations can be reduced (simplified):
2x+8y = 6 => x + 4y = 3
15x + 20y = 15 => 3x + 4y = 3
Let's use the elimination by addition and subtraction method. Multiply the first equation by -1, obtaining
-x - 4y = -3
Add the second 3x + 4y = 3
equation to the
first.
We get: 2x = 0.
Thus, x = 0. Substituting 0 for x in the 1st original equation yields:
2(0) + 8y = 6. Then y = 6/8, or y = 3/4.
The solution is (0, 3/4).
C. would be the correct device to use in trials.
But the actual probability is:
(1-1/4)^5
243/1024
(about 23.73% chance none of the five chose vanilla)
Answer:
Probability that average height would be shorter than 63 inches = 0.30854 .
Step-by-step explanation:
We are given that the average height of 20-year-old American women is normally distributed with a mean of 64 inches and standard deviation of 4 inches.
Also, a random sample of 4 women from this population is taken and their average height is computed.
Let X bar = Average height
The z score probability distribution for average height is given by;
Z = 
~ N(0,1)
where, 
= population mean = 64 inches
= standard deviation = 4 inches
n = sample of women = 4
So, Probability that average height would be shorter than 63 inches is given by = P(X bar < 63 inches)
P(X bar < 63) = P( < 
) = P(Z < -0.5) = 1 - P(Z <= 0.5)
= 1 - 0.69146 = 0.30854
Hence, it is 30.85% likely that average height would be shorter than 63 inches.
You’re answer would be B (-6, 1) (-1, -1)
