Answer:
7 or 8
Step-by-step explanation:
Robbie was given $80.
His admission costs $15.50
80 - 15.50 = $64.50
He anticipates the cost of food at the fair will be $25.
64.50 - 25 = $39.50
What is the maximum number of rides he can take at the Fair?
(Total $ after admission and cost of food/ ride cost)
$39.50 / $5 = 7.9
I think they should keep it around, even if it might not be the most efficient strategy. After all, what if you need to solve a problem using multiple strategies?
If 14 out of 20 is correct, then that is : 14/20 = 0.70 = 70%
Answer:
(3x - 5)------------------->
Step-by-step explanation:
look at the work
Ab = (7x-6) → b = (7x-6)/a (1)
bc = (12-2x) → b = (12-2x)/c (2)
Since (1) = (2) → (7x-6)/a = (12-2x)/c OR a/c = (7x-6)/(12-2x) (3)
Multiply both numerators of (3) by the SQUARE of their respective denominators;
(a*c²)/c = (7x-6)(12-2x)²/(12-2x)
Now simplify:
ac = (7x-6)(12x-2x) or ac = -14x² + 96x - 72