The relationship between energy of a single photon and its wavelength can be determined using the formula E=hc/lambda where E is energy, h is Planck's constant, c is the speed of light, and lambda is photons.
Before being able to solve for energy, need to convert nanometers to meters.
407 nm (1 m/1 x 10^9 nm) = 4.07 x 10^-7 m
Then plug in the values we know into the equation.
E h(Planck's constant) c(speed of light)
E = (6.63 x 10^-34 Js)(3 x 10^8 m/s) / 4.07 x 10^-7 m (lambda)
E=(0.000000000000000000000000000000000663js)(300,000,000m/s)=1.989×10^-25j/ms
E=1.989x10^-25j/ms /{divided by} 4.07x10^-7m = 4.8869779x10^-33 J (the meters cancel out)
E = 4.89 x 10^-33 J
This gives us the energy in Joules of a single photon. Now, we can find the number of photons in 0.897 J
0.897J / 4.89 x 10^-33 J = ((0.897 J) / 4.89) x ((10^(-33)) J) = 1.8343558 x 10^-34
1.83435583 × 10-34m4 kg2 / s4 photons
Answer : The value of diffusion coefficient is, 
Explanation :
Formula used :
where,
D = diffusion coefficient = ?
= 
= 
R = gas constant = 8.314 J/mol.K
T = temperature = 
Now put all the given values in the above formula, we get:
Thus, the value of diffusion coefficient is,
Answer: A volume of 600 mL of 3.0 M 
solution can be prepared by using 100.0 mL OF 18 M .
Explanation:
Given: 
= ?, 
, 
Formula used to calculate the volume is as follows.
Substitute the values into above formula as follows.
Thus, we can conclude that a volume of 600 mL of 3.0 M solution can be prepared by using 100.0 mL OF 18 M .
Answer:
i think the answer is helium (top right in periodic table)
Answer:
<h3>The answer is 2.67 g/cm³</h3>
Explanation:
The density of a substance can be found by using the formula
From the question
mass of metal = 32 g
volume = 12 cm³
The density is
We have the final answer as
<h3>2.67 g/cm³</h3>
Hope this helps you
