Answer:
The standard enthalpy of formation of HgO is -90.7 kJ/mol.
Explanation:
The reaction between Hg and oxygen is as follows.
From the given,
Molar mass of HgO = 216.59 g/mol
Mass of HgO decomposed = 18.5 g
Amount of heat absorbed = 7.75 kJ
From the reaction,
The standard enthalpy of formation = 
During the decomposition of 1 mol of HgO , 90.7 kJ of energy absorbed.
For the formation of 1 mol of HgO , 90.7 kJ of energy is release
Therefore, the enthalpy of formation of mercury(II)Oxide is -90.7 kJ/mol
Answer:
Explanation:
The first law of Thermodynamics is known as Conservation because it explains that energy is always maintained within a closed system and cannot be created or destroyed. Therefore, this is observed when there is no longer change in temperature in a system. Mainly because the energy is not being transferred to and from another system. Without this transfer of energy, the energy itself gets conserved within the system and the temperature no longer fluctuates.
The transuranium synthesis process involves creating a transuranium element through the transmutation of a lighter element.
So, the answer would be the C the transmutation of a lighter element.
Transuranium elements are the elements with atomic numbers greater than 92. All of these elements are unstable and decay radioactively into other elements.
Answer:
2%
Explanation:
oriented C-2, and (3) the minimizing of the number of ... (2) L. A. Mitscher, J. K. Paul, and L. Goldman,Experientia, 19, 195. (1963). ... SOzCeHiBr)3 in 147 ml. of anhydrous methanol containing 0.37 ... bicarbonate and saturated sodium chloride solution, and dried ... determined in 2% chloroform solution; infrared spectra on.
