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Anastasy [175]
3 years ago
10

In 36 hours the amount of radioactive substance has reduced from 80 mg to 10 mg. What is the half-life of this isotope?

Chemistry
1 answer:
rusak2 [61]3 years ago
6 0
Half-life refers to the time taken for half of the atoms in a radioactive substance to decay. Therefore in 1 half-life the 80 mg of substance will reduce to 40 mg. In another half-life it will reduce from 40 mg to 20 mg, then in a third half-life from 20 mg to 10 mg. Therefore the half-life is equal to the total time taken to decay from 80 mg to 10 mg divided by 3:
t(1/2) = 36 hours / 3 = 12 hours.
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Calculate the concentration of hi when the equilibrium constant is 1x10^5
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Answer is: concentration of hydrogen iodide is 6 M.

Balanced chemical reaction: H₂(g) + I₂(g) ⇄ 2HI(g).
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Based on the information, what is the balanced chemical equation representing the burning of butane?
kompoz [17]

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Explanation:

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C4H10 + O2 —> CO2 + H20

Considering the equation, it is evident that it not balanced. Now let us balance the equation as shown below;

There are a total of 4 carbon atoms on the left and 1 carbon atom on the right. It can be balanced by putting 4 in front of CO2 as shown below:

C4H10 + O2 —> 4CO2 + H20

Next, there are 10 hydrogen atoms on the left and 2 hydrogen atoms on the right. Therefore to balance it, put 5 in front of H2O as shown below:

C4H10 + O2 —> 4CO2 + 5H20

Now, there are a total of 13 oxygen atoms on the right and 2 at the left. To balance it, put 13/2 in front of O2

as shown below

C4H10 + 13/2O2 —> 4CO2 + 5H20

Now we multiply through by 2 clear off the fraction and we obtained:

2C4H10 + 13O2 —> 8CO2 + 10H20

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