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finlep [7]
3 years ago
5

How will you prepare 10mL of 0.050M HCl from a 0.10M solution of HCl

Chemistry
1 answer:
vichka [17]3 years ago
7 0
M₁V₁ = M₂V₂

(0.050M)*(10 mL) = (0.10M)*(x)

x = 5 mL

You would take 5 mL of the 0.10 M solution of HCl and add 5 mL of deionized water. Therefore, the total volume will be 10 mL and it will have a molarity of 0.050.
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According to the pattern of carbon and hydrogen atoms in alkenes, if a molecule has three carbon atoms, how many hydrogen atoms
Gekata [30.6K]
 <span>6. 

Because the general formula for alkenes is CnH2n</span>
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3 years ago
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I don't know how to do this, pls help!
Aliun [14]
Cations from smallest to largest
Li⁺ ,Na⁺, K⁺ (from Periodic Table, the bigger number of period, the bigger size, of atom, so the bigger size of cation)

1) LiF smaller  cation then KF
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</span><span>The lattice energy increases as cations get smaller, as shown by LiF and KF.
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7 0
3 years ago
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What is the volume of 88.2 g of silver metal (density = 10.50 g/cm^3)
babymother [125]

Answer:

The answer is

<h2>8.4 mL</h2>

Explanation:

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volume =  \frac{mass}{density}

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density = 10.5 g/cm³

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volume =  \frac{88.2}{10.5}

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<h3>8.4 mL</h3>

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3 years ago
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Which of the following reactions have a positive ΔSrxn? Check all that apply.
PolarNik [594]

Answer:

The reactions that have a <em>positive ΔS rxn </em>are the first and the fourth choices:

  • <em>2A(g) + B(s) → 3C(g)</em>

  • <em>2A(g) + 2B(g) → 5C(g)</em>

Explanation:

<em>ΔS rxn </em>is the change of entropy of the chemical reaction.

ΔS rxn = S after reaction - S before reaction.

Therefore, a positive ΔS rxn  means that the entropy after the reaction is greater than the entropy before the reaction.

You may use some assumptions to predict whether a reaction will lead an increase or decrease of the entropy.

First, assume that all the non-shown conditions, such as temperature and pressure, are constant.

Under that assumption, and from the meaning of entropy as a measure of the disorder or randomness of a system you can predict the sign of the change of entropy.

  • <em><u>2A(g) + B(s) → 3C(g)</u></em>

        1)  The solid compounds, B(s) in this case, are very ordered and so they have low entropy.

        2) Gas molecules are highly disordered (scattered), and the greater the number of molecules of the gas the larger the entropy, S).

Hence, since the product side shows 3 gas molecules and the reactant side shows 2 gas molecules and 1 solid molecule, you predict that the products have a larger entropy than the reactants, meaning an increase in entropy: <em>ΔS rxn is positive.</em>

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Using the same reasoning, 3 gas molecules in the  reactant side have more entropy than 1 molecule in the product side, and so the reaction leads to a decrease in the entropy: ΔS rxn is negative

  • <u><em>A(g) + B(g) → C(g)</em></u>

Again, 2 gas molecules in the  reactant side have more entropy than 1 molecule in the product side, and so the reaction leads to a decrease in the entropy: ΔS rxn is negative

  • <u><em>2A(g) + 2B(g) → 5C(g)</em></u>

With the same reasoing, 5 molecules in the product side, lets you predict that will have more entropy than 4 molecules in the reactant side, and, the entropy will increase: <em>ΔS rxn is positive.</em>

6 0
4 years ago
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