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4 years ago

The chief function of muscles is _____. contraction absorption excretion protection

Chemistry

2 answers:

Vilka [71]4 years ago

8 0

Contraction the progress in which a muscle becomes or is made shorter and stronger :))))))))))

denpristay [2]4 years ago

3 0

Answer:

The correct answer is the first option: contraction.

Explanation:

Hello!

Let's solve this!

Muscles are structures or tissues with a main function that is to contract. This happens so that we can perform each of our movements.

They are divided into smooth muscles and skeletal muscles.

We conclude that the correct answer is the first option: contraction.

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5. A sample of gas occupies 1.55 L at 27 degrees Celsius and 1.00 atm pressure. What will the volume be if the pressure is incre

Sergio039 [100]

Answer:

The volume will be 0.031 L

Explanation:

Since temperature is constant, Boyle's law is applied in this case.

Boyle's law States that at constant temperature, the volume of a given mass of a gas is inversely proportional to it's pressure.

From this statement it was deduced that P1V1 = P2V2

From the question, P1 = 1atm, V1 = 1.55L, P2 = 50 atm and V2 is to be calculated.

V2 = P1V1/P2

= 1×1.55÷50

=0.031 L

5 0

3 years ago

A metal X from two oxide A and B .3.oogm of A and B contain 0.72 and 1.16g of oxygen respectively.calculate the maases of metal

devlian [24]

Answer:

Explanation:

Firstly, we have to determine the mass of metal X. We can do that by interpreting the first and second statement mathematically.

Metal X can form 2 oxides (A and B).

A + B = 3g

The mass of oxygen in A is 0.72g and the mass of oxygen in B is 1.16g.

The mass of metal X in the two oxides will be the same because it's the same metal.

Thus, we represent the mass of the metal in the two oxides as 2X.

2X + 0.72 + 1.16 = 3

2X + 1.88 = 3

2X = 3 - 1.88

2X = 1.12

X = 0.56

Thus, 0.56 g of the metal combines with 0.72g of oxygen in A and 1.16 g of oxygen in B.

Thus, mass of metal (X) in 1g of oxygen in A is

0.56g ⇒ 0.72g

X ⇒ 1

X = 1 × 0.56/0.72

X = 0.78 g

Hence, 0.78g of the metal will combine with 1g of oxygen for A

Also, mass of metal (X) in 1g of oxygen in B is

0.56g ⇒ 1.16g

X ⇒ 1g

X = 1×0.56/1.16

X = 0.48 g

Thus, 0.48g of the metal will combine with 1g of oxygen for B

6 0

3 years ago

Why pie bond are not perticipate in hybridaization

DedPeter [7]

The first bond between two atoms is always a sigma bond and the other bonds are always pi bonds and a hybridized orbital cannot be involved in a pi bond. Thus we need to leave one electron (in case of Carbon double bond) to let the Carbon have the second bond as a pi bond.

3 0

3 years ago

Jessica jogs on a path that is 25 km long to get to a park that is south of the jogging path if it takes us a good 2.5 hours the

zysi [14]

She jogs 10km per hour. Hope this helps :)

3 0

3 years ago

1. Which of the following nuclear equations is correctly balanced? (choices attached)

lawyer [7]

1. Balancing nuclear equations

Answer:

$_{18}^{37}\text{Ar} + _{-1}^{0}\text{e} \rightarrow _{17}^{37}\text{Cl}$

Explanation:

The main point to remember in balancing nuclear equations is that the sums of the superscripts (the mass numbers) and the subscripts (the nuclear charges) must balance.

Mass numbers: 37 + 0 = 37; balanced.

Charges: 18 + 1 = 17; balanced

B is wrong. Mass numbers not balanced. 6 +2(1) ≠ 4 + 3.

C is wrong. Mass numbers not balanced. 254 + 4 ≠ 258 + 2(1).

D is wrong. Mass numbers not balanced. 14 + 4 ≠ 17 + 2.

===============

2. Amount remaining

Answer:

D. 5.25 g

Explanation:

The half-life of Th-234 (24 da) is the time it takes for half the Th to decay.

After one half-life, half (50 %) of the original amount will remain.

After a second half-life, half of that amount (25 %) will remain, and so on.

We can construct a table as follows:

No. of Fraction Amount

half-lives t/(da) remaining remaining/g

1 24 ½ 21.0

2 48 ¼ 10.5

3 72 ⅛ 5.25

4 96 ¹/₁₆ 2.62

We see that 72 da is three half-lives, and the amount of Th-234 remaining is 5.25 g.

===============

3. Calculating the half-life

Answer:

a. 2.6 min

Explanation:

The fraction of the original mass remaining is 1.0 g/4.0 g ≈ ¼.

We saw from the previous table that it takes two half-lives to decay to ¼ of the original amount.

2 half-lives = 5.2 min Divide both sides by 2

1 half-life = 5.2 min/2 = 2.6 min

7 0

3 years ago