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vesna_86 [32]
3 years ago
8

How many carbons atoms are in propane?

Chemistry
2 answers:
Zigmanuir [339]3 years ago
6 0
Three Carbon Atoms in the chain all connected by single bonds
kompoz [17]3 years ago
4 0
I believe there are three carbon atoms in propane
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Lewis dot structure for N3-
labwork [276]

Answer :

The steps involved in the electron dot structure of N^{3-} are :

First we have to determine the total number of valence electron in N^{3-}.

Number of valence electrons in N = 5

The charge on N is (-3). So, we add 3 electrons.

Total number of valence electrons = 5 + 3 = 8 electrons

The image is shown below.

4 0
3 years ago
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Find the % composition for each element in Zn(CIO3)2
bezimeni [28]

Zn = 28.15%

Cl = 30.53%

O = 41.32%

<h3>Further explanation</h3>

Given

Zn(CIO3)2 compound

Required

The % composition

Solution

Ar Zn = 65.38

Ar Cl = 35,453

Ar O = 15,999

MW Zn(CIO3)2 = 232.3

Zn = 65,38/232.3 x 100% = 28.15%

Cl = (2 x 35.453) / 232.3 x 100% = 30.53%

O = (6 x 15.999) / 232.3 x 100% = 41.32%

7 0
2 years ago
Answer this question:
almond37 [142]

Answer:

Meteorologists look at data help from the computer about temperature, pressure, humidity, and wind speed, among many other data points to try and accurately predict the weather.

5 0
2 years ago
How many PO43? ions are in a mole of K3PO4?
adoni [48]

K₃PO₄ → 3K⁺ (aq) + PO₄³⁻(aq)

One mole of PO₄³⁻ ion gets dissociated from one mole of K₃PO₄

As per the definition of Avogadro's number, 1 mole = 6.022 x 10²³ ions

One mole of PO₄³⁻ ions x  (6.022 x 10²³ ions/ 1 mole of PO₄³⁻ ions )

= 6.022 x 10²³ ions

Therefore , there are 6.022 x 10²³ PO₄³⁻ ions in a mole of K₃PO₄.

7 0
3 years ago
10mL volume of 75mM EtOH is necessary for an experiment. What volumes of 1M EtOH and water should be mixed to obtain the working
kenny6666 [7]

Answer: Volume of the 1M EtOH and water should be 0.75 ml and 9.25 ml respectively to obtain the working concentration.

Explanation:

According to the dilution law,

C_1V_1=C_2V_2

where,

C_1 = molarity of stock solution = 1M

V_1 = volume of stock solution = ?

C_2 = molarity of diluted solution = 0.075 M    (1mM=0.001M)

V_2 = volume of diluted solution = 10 ml

Putting in the values we get:

1M\times V_1=0.075M\times 10ml

V_1=0.75ml

Thus 0.75 ml of 1M EtOH is taken and (10-0.75)ml = 9.25 ml of water is added to make the volume 10ml.

Therefore, volume of the 1M EtOH and water should be 0.75 ml and 9.25 ml respectively to obtain the working concentration

3 0
3 years ago
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