10.2.5 mg/kg I think this was a confusing question
Answer:
Option D. 0.9mol x 2mol Fe /3mol CO2 x 55.845g Fe /1mol Fe
Explanation:
The balanced equation for the reaction is given below:
3CO + Fe₂O₃ → 2Fe + 3CO₂
Molar Mass of Fe = 56g/mol
From the balanced equation above,
3 moles of CO2 produced (2 mol Fe x 55.845g Fe.
Therefore, 0.9 mole of CO2 will produce = 0.9mol x 2mol Fe /3mol CO2 x 55.845g Fe /1mol Fe
If 162.35 g aluminum hydroxide are dissolved in 6750 mL of solution, the concentration of the solution is 0.308M
<h3>How to calculate concentration?</h3>
The concentration of a solution can be calculated using the following formula:
Molarity = no of moles ÷ volume (L)
However, the number of moles in 162.35g of Al(OH)3 must be calculated as follows:
Molar mass of Al(OH)3 = 78g/mol
no of moles = 162.35g ÷ 78mol
no of moles = 2.08mol
Molarity = 2.08mol ÷ 6.75L
Molarity = 0.308M
Therefore, if 162.35 g aluminum hydroxide are dissolved in 6750 mL of solution, the concentration of the solution is 0.308M.
Learn more about molarity at: brainly.com/question/2817451
Answer
2.1 x 10 ^23
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