x = 3y - 1
2y + x = x + 18
2y + 3y - 1 = 3y - 1 + 18
5y - 1 = 3y + 17
2y = 18
y = 9
x = 3(9) - 1
x = 27 - 1
x = 26
Answer:
a
Since the integral has an infinite discontinuity, it is a Type 2 improper integral
b
Since the integral has an infinite interval of integration, it is a Type 1 improper integral
c
Since the integral has an infinite interval of integration, it is a Type 1 improper integral
d
Since the integral has an infinite discontinuity, it is a Type 2 improper integral
Step-by-step explanation:
Considering a

Looking at this we that at x = 3 this integral will be infinitely discontinuous
Considering b

Looking at this integral we see that the interval is between
which means that the integral has an infinite interval of integration , hence it is a Type 1 improper integral
Considering c

Looking at this integral we see that the interval is between
which means that the integral has an infinite interval of integration , hence it is a Type 1 improper integral
Considering d

Looking at the integral we see that at x = 0 cot (0) will be infinity hence the integral has an infinite discontinuity , so it is a Type 2 improper integral
C = 2πr
C = 2(3.14)(0.8)
C = 2(2.512)
C = 5.024 m
The answer is C.
486 if your looking for the total
C - 10 = g
L - 5 = C
g = 5
then altogether he finds
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