Hi, It is well simples:
The distance between two points is :
d( A, B) = √[ (xb - xa)^2+(yb - ya)^2+(zb - za)^2]
Then,
A = (xa, ya, za )
B = (xb , yb , zb)
We know:
A = ( 2 ,0 ,-2)
And,
B = (5 , -4 , 6)
___________
xb - xa = 5-2 <=> 3
yb - ya = -4 - 0 <=> -4
zb - za = 6 - (-2) <=> 8
Then us stay:
d( A, B) = √[ (3)^2 + (-4)^2+(8)^2]
= √( 9 + 16 + 64)
= √( 25 + 64)
= √(89)
Answer:
Step-by-step explanation:
Given: See Attachment
Required
Determine the length of the legs
To do this, we apply Pythagoras theorem.
In this case:
Open Bracket
Collect Like Terms
Solving using quadratic formula:
So:
or 
Since, x can't be negative, then:
One of the leg is:
Rate/ speed = distance / time;
= 1/2mile / 300 seconds;
= 0.001666666..... mile/second
Step-by-step explanation:
2x - 3y = 9
2x + 3y = 3
__________ -
-6y = 6
y = -1
2x - 3y = 9
2x - 3(-1) = 9
2x - (-3) = 9
2x = 12
x = 6
Answer:
15.71 ft
Step-by-step explanation:
Given that:
width of the circular track = 2.5ft
Suppose the radius of the inner circle is 57 ft since it is not given
Then the radius of the outer circle = (2.5 + 57) ft = 59.5 ft
The circumference of a circle = 2πr
For inner circle now, the circumference = 2 × π × 57 ft
For inner circle now, the circumference = 358.14 ft
For the outer circle, the circumference = 2 × π × 59.5 ft
For the outer circle, the circumference = 373.85 ft
The difference between the circumference of the outer wheel from the inner wheel shows how farther does a wheel on the outer rail travel than a wheel on the inner rail of the track in one turn
∴
= ( 373.85 - 358.14 ) ft
= 15.71 ft
