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zavuch27 [327]
3 years ago
8

Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the corre

ct position in the answer box. Release your mouse button when the item is place. If you change your mind, drag the item to the trashcan. Click the trashcan to clear all your answers. For the right triangle shown, the lengths of two sides are given. Find the third side. Leave your answer in simplified, radical form. a = 5, b = 10, c =

Mathematics
2 answers:
nordsb [41]3 years ago
4 0

Answer:


Step-by-step explanation:

for right-angled triangle: a^2 + b^2 = c^2

given a = 5 n b = 10

c^2 = 5^2 + 10^2

= 25 + 100

= 125

c = sqrt(125)

= 5*sqrt(5)

Alla [95]3 years ago
3 0

Answer:

c = 5√5

Step-by-step explanation:

It would probably be better if you remove the first part as it is not related to the question itself; just how to answer it.


For the right triangle shown, the lengths of two sides are given. Use Pythagoras Theorem to find the third side:

c2 = a2 + b2

= 5*5 + 10*10

= 125

c = √125

= √(25*5)

= √25*√5

= 5√5


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Use the zero product property to find the solutions to the equation (x + 2) (x + 3) = 12
Inessa05 [86]

Answer:

The solution of the equations are -6 and 1

Step-by-step explanation:

* <em>Lets explain how to solve the problem</em>

- We want to find the solution of the equation (x + 2) (x + 3) = 12

- <em>At first lets use the Foil method to multiply the two brackets</em>

 (x + 2) (x + 3) = (x)(x) + (x)(3) + (2)(x) + (2)(3)

 (x + 2) (x + 3) = x² + 3x + 2x + 6 ⇒ add the like term

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∵ (x + 2) (x + 3) = 12

∴ x² + 5x + 6 = 12

- Subtract 12 from both sides

∴ x² + 5x - 6 = 0

- <em>Factorize the left hand side</em>

∵ x² = (x)(x)

∵ -6 = 6 × -1

∵ 6x + -1x = 5x

∴ (x + 6)(x - 1) = 0

- <em>Lets use the zero product property </em>

∵ (x + 6)(x - 1) = 0

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- Subtract 6 from both sides

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- Add 1 to both sides

∴ x = 1

∴ The solution of the equations are -6 and 1

6 0
2 years ago
Read 2 more answers
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<1 and <2 are complementary : given
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<2 congruent <4 : given
<3 congruent <4 : transitive property
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3 years ago
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