The food stand at the zoo sold 2514

Question Help A manufacturer ships toasters in cartons of 1010. In each carton, they estimate a 1010% chance that any one of t

natta225 [31]

Answer:

The probability that there will be repair exactly 3 toaster is 0.0574.

Step-by-step explanation:

Binomial Distribution:

A discrete random variable X having the set {0,1,2,3......,n} as the spectrum, is said have a binomial distribution with parameter n= number of trials and p=probability of number of success on an individual trial, if the p.m.f (probability mass function) of X given by,

$P(X=x)=C(n,x)p^x(1-p)^{n-x}$ x=0,1,2,......,n

=0 elsewhere

where 0<p<1 and n is a positive integer.

Total number of toaster in cartons(n) = 10.

Probability of number of success on an individual trial p= 10% = 0.10

$\therefore P(X=3)= C(10,3)(0.10)^3(1-0.10)^{10-3}$

$=\frac{10!}{3!(10-3)!}(0.10)^3)(0.90)^7$

=0.0574

The probability that there will be repair exactly 3 toaster is 0.0574.

6 0

3 years ago

Complete the statement to describe how to convert ounces to pounds?

Digiron [165]

Answer:

to find the weight in pounds, divide the number of ounces by the unit rate, 16 ounces per pound.

6 0

3 years ago

Evan went to the park and saw four animals.

dsp73

Answer:

He saw 1 duck and 3 dogs.

Step-by-step explanation:

Given:

Evan went to the park and saw four animals.

Each animal was either a duck or a dog.

He saw a total of 14 legs.

Now, to find the number of each animal he had seen.

Let the number of duck be $x.$

And the number of dog be $y.$

So, total number of animals:

$x+y=4\\y=4-x$

Now, the total number of legs he did see:

As we know the legs of a duck are 2 and a dog are 4.

$2x+4y=14\\2x+4(4-x)=14\\2x+16-4x=14\\-2x+16=14$

Adding both sides by -16 we get:

$-2x=-2$

Dividing both sides by -2 we get:

$x=1$

The number of duck = 1.

Now, putting the value of $x$ in above equation we get:

$y=4-x$

$y=4-1\\y=3.$

The number of dogs = 3.

Therefore, he saw 1 duck and 3 dogs.

4 0

3 years ago

Two lighthouses are located 75 miles from one another on a north-south line. If a boat is spotted S 40o E from the northern ligh

yuradex [85]

Answer:

The northern lighthouse is approximately $24.4\; \rm mi$ closer to the boat than the southern lighthouse.

Step-by-step explanation:

Refer to the diagram attached. Denote the northern lighthouse as $\rm N$ , the southern lighthouse as $\rm S$ , and the boat as $\rm B$ . These three points would form a triangle.

It is given that two of the angles of this triangle measure $40^{\circ}$ (northern lighthouse, $\angle {\rm N}$ ) and $21^{\circ}$ (southern lighthouse $\angle {\rm S}$ ), respectively. The three angles of any triangle add up to $180^{\circ}$ . Therefore, the third angle of this triangle would measure $180^{\circ} - (40^{\circ} + 21^{\circ}) = 119^{\circ}$ (boat $\angle {\rm B}$ .)

It is also given that the length between the two lighthouses (length of $\rm NS$ ) is $75\; \rm mi$ .

By the law of sine, the length of a side in a given triangle would be proportional to the angle opposite to that side. For example, in the triangle in this question, $\angle {\rm B}$ is opposite to side $\rm NS$ , whereas $\angle {\rm S}$ is opposite to side ${\rm NB}$ . Therefore:

$\begin{aligned} \frac{\text{length of NS}}{\sin(\angle {\rm B})} = \frac{\text{length of NB}}{\sin(\angle {\rm S})} \end{aligned}$ .

Substitute in the known measurements:

$\begin{aligned} \frac{75\; \rm mi}{\sin(119^{\circ})} = \frac{\text{length of NB}}{\sin(21^{\circ})} \end{aligned}$ .

Rearrange and solve for the length of $\rm NB$ :

$\begin{aligned} & \text{length of NB} \\ =\; & (75\; \rm mi) \times \frac{\sin(21^{\circ})}{\sin(119^{\circ})} \\ \approx\; & 30.73\; \rm mi\end{aligned}$ .

(Round to at least one more decimal places than the values in the choices.)

Likewise, with $\angle {\rm N}$ is opposite to side ${\rm SB}$ , the following would also hold:

$\begin{aligned} \frac{\text{length of NS}}{\sin(\angle {\rm B})} = \frac{\text{length of SB}}{\sin(\angle {\rm N})} \end{aligned}$ .

$\begin{aligned} \frac{75\; \rm mi}{\sin(119^{\circ})} = \frac{\text{length of SB}}{\sin(40^{\circ})} \end{aligned}$ .

$\begin{aligned} & \text{length of SB} \\ =\; & (75\; \rm mi) \times \frac{\sin(40^{\circ})}{\sin(119^{\circ})} \\ \approx\; & 55.12\; \rm mi\end{aligned}$ .

In other words, the distance between the northern lighthouse and the boat is approximately $30.73\; \rm mi$ , whereas the distance between the southern lighthouse and the boat is approximately $55.12\; \rm mi$ . Hence the conclusion.

4 0

3 years ago

I WILL MARK YOU BRAINLIEST IF YOU ANSWER

liberstina [14]

Answer:

29.25 Pound sterling

6 0

3 years ago

Read 2 more answers