Answer:
Let us say the domain in the first case, has the numbers. And the co-domain has the students, .
Now for a relation to be a function, the input should have exactly one output, which is true in this case because each number is associated (picked up by) with only one student.
The second condition is that no element in the domain should be left without an output. This is taken care by the equal number of students and the cards. 25 cards and 25 students. And they pick exactly one card. So all the cards get picked.
Note that this function is one-one and onto in the sense that each input has different outputs and no element in the co domain is left without an image in the domain. Since this is an one-one onto function inverse should exist. If the inverse exists, then the domain and co domain can be interchanged. i.e., Students become the domain and the cards co-domain, exactly like Mario claimed. So, both are correct!
Answer:
It is not the same
Step-by-step explanation:
Is 5/2 greater than 2/5? Is 5/2 bigger than 2/5? Is 5/2 larger than 2/5? These are all the same questions with one answer.
When comparing fractions such as 5/2 and 2/5, you could also convert the fractions (if necessary) so they have the same denominator and then compare which numerator is larger.
To get the answer, we first convert each fraction into decimal numbers. We do this by dividing the numerator by the denominator for each fraction as illustrated below: 5/2 = 2.5
2/5 = 0.4 Therefore, 5/2 is greater than 2/5 and the answer to the question "Is 5/2 greater than 2/5?" is yes.
Answer:
The sum of the roots is 0.5
Step-by-step explanation:
<u><em>The correct question is</em></u>
What is the sum of the roots of 20x^2-10x-30
we know that
In a quadratic equation of the form
The sum of the roots is equal to
in this problem we have
so

substitute
<u><em>Verify</em></u>
Find the roots of the quadratic equation
The formula to solve a quadratic equation is equal to


substitute





The roots are x=-1 and x=1.5
The sum of the roots are
----> is ok
Both B and D are 3rd degree, but only D is a 3rd degree binomial because it has only 2 terms. The answer is D.