Answer:
The impedance of the inductor is ω L:
This is in parallel wth R giving a resistance of the parallel combination:
1 / Rp = 1 / ω L + 1 / R
Rp = (ω L * R) / (ω L + R) for the impedance of the parallel combination
Total resistance (impedance) Rt = Rp + R2 = Z
One can use the term impedance to show that the resulting current is not in phase with the resulting voltage
phase angle φ - cos φ = ω L / Rt
V = I Z shows the relation of voltage and urrent
Answer: T = 472.71 N
Explanation: The wire vibrates thus making sound waves in the tube.
The frequency of sound wave on the string equals frequency of sound wave in the tube.
L= Length of wire = 26cm = 0.26m
u=linear density of wire = 20g/m = 0.02kg/m
Length of open close tube = 86cm = 0.86m
Sound waves in the tube are generated at the second vibrational mode, hence the relationship between the length of air and and wavelength is given as
L = 3λ/4
0.86 = 3λ/4
3λ = 4 * 0.86
3λ = 3.44
λ = 3.44/3 = 1.15m.
Speed of sound in the tube = 340 m/s
Hence to get frequency of sound, we use the formulae below.
v = fλ
340 = f * 1.15
f = 340/ 1.15
f = 295.65Hz.
f = 295.65 = frequency of sound wave in pipe = frequency of sound wave in string.
The string vibrated at it fundamental frequency hence the relationship the length of string and wavelength is given as
L = λ/2
0.26 = λ/2
λ = 0.52m
The speed of sound in string is given as v = fλ
Where λ = 0.52m f = 295.65 Hz
v = 295.65 * 0.52
v = 153.738 m/s.
The velocity of sound in the string is related to tension, linear density and tension is given below as
v = √(T/u)
153.738 = √T/ 0.02
By squaring both sides
153.738² = T / 0.02
T = 153.738² * 0.02
T = 23,635.372 * 0.02
T= 472.71 N
The answer to your question is A.
Answer:Both will continue traveling at the same speed because there is no friction.
Explanation: Gravitational force or pull is the force acting to attract all object in and around the Earth to the center of the Earth. The Earth's Gravitational force acts as a Bar magnet.
When objects are working outside the impact of the force of Gravity,it will not matter whether the objects are of the same size or wether one is heavier than the other,in this case both objects will move at the same speed as there is no impact of the Force of Gravity.
For maximum radiation protection the suggested distance between array fan-beam scanner source and the operator is 2m.
The Fan beam 5 position reference system (PRS) uses accurate time-of-flight laser technology to determine vessel position relative to custom reflectors.
A fan beam allows only the measurement of the azimuth angle. A fan beam, one with a narrow beam width in azimuth and a broad beam width in elevation, can be obtained by illuminating an asymmetrical section of the paraboloid.
The operators’ desk should be positioned at least 1m away from a pencil beam, and at least 2m from a fan-beam system. Some older models, that are not now common, require a distance of 3.5 m.
To learn more about scanner here
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