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2 years ago

Need help ASAP

Physics

2 answers:

mina [271]2 years ago

8 0

Answer:

1.radio wave

2. radio wave

3.broadcasting

devlian [24]2 years ago

5 0

Answer:

cell pohnes convert sound waves into radio waves

electromagnetic waves used in cellphone communications are called: radio waves

To send out a radio signal far and wide.. it is called: broadcast

Explanation:

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What happens to the density of a fluid as it temperature increases/decreases?

Elan Coil [88]

Let's look at the density of water at 25 deg C and compare that to a higher temperature, 80 deg C. The density decreases from 0.9970 g/mL to 0.9718 as it is heated. This makes sense because, as heat is added to the liquid water, there is greater kinetic energy of the molecules and there are also more vibrations of the water molecules. Together these mean that each H2O unit in liquid water takes up more space as the temperature increases.

4 0

1 year ago

A 3,273N force is applied to a 223kg mass. What is the acceleration of the mass?

Alexxandr [17]

Answer:

acceleration =

$14.67ms {}^{ - 2}$

Explanation:

force = mass × acceleration
acceleration = force / mass
a = f / m

we know that f = 3273 N, M = 223 kg

a = 3273 / 223
a = 14.67 m/s^2

 i hope it helped.....

8 0

2 years ago

A sound wave from a siren has an intensity of 111.2 W/m2 at a certain point, and a second sound wave from a nearby ambulance has

Kazeer [188]

Answer:

The intensity level of the sound wave due to the ambulance is 153.5 dB.

Explanation:

The intensity level of the sound wave due to the ambulance can be calculated using the following equation:

$\beta = 10log(\frac{I}{I_{0}})$

Where:

I: is the intensity of the sound wave from a siren = 111.2 W/m²

I₀: is the reference intensity = 1.0x10⁻¹² W/m²

$\beta = 10log(\frac{111.2 W/m^{2}}{1.0 \cdot 10^{-12} W/m^{2}}) = 140.5 dB$

Now, since the second sound wave from a nearby ambulance has an intensity level 13 dB we have:

$I_{a} = 13 dB + 140.5 dB = 153.5 dB$

Therefore, the intensity level of the sound wave due to the ambulance is 153.5 dB.

I hope it helps you!

5 0

2 years ago

Why are astronauts weightless in the Space Station? You may find it helpful to watch the video "Newton's Laws of Motion." Why ar

Zolol [24]

Answer:

B) Because the Space Station is constantly in free-fall around the Earth.

Explanation:

Anything that is falling experiences an upward force on them. For example when a person is going down in a lift they will experience something that is pushing them upwards. This happens due to the fact that the total acceleration the body is feeling is less than the acceleration due to graviity.

The force on a body which is falling is

$F=m(g-a)$

Where,

m = Mass of object

g = acceleration due to gravity

a = acceleration the object is experiencing.

a = g. So, the force becomes zero and the object experiences weightlessness.

Hence, the astronauts in the space station experience weightlessness due to fact that the Space Station is constantly in free-fall around the Earth.

7 0

2 years ago

A flat surface is in a uniform magnetic field. Given only the area of the surface and the magnetic flux through the surface, it

Tasya [4]

Answer:

Given the area A of a flat surface and the magnetic flux through the surface $\Phi$ it is possible to calculate the magnitude $\frac{\Phi}{A}=B\ cos \theta$ .

Explanation:

The magnetic flux gives an idea of how many magnetic field lines are passing through a surface. The SI unit of the magnetic flux $\Phi$ is the weber (Wb), of the magnetic field B is the tesla (T) and of the area A is ( $m^{2}$ ). So 1 Wb=1 T.m².

For a flat surface S of area A in a uniform magnetic field B, with $\theta$ being the angle between the vector normal to the surface S and the direction of the magnetic field B, we define the magnetic flux through the surface as:

$\Phi=B\ A\ cos\theta$

We are told the values of $\Phi$ and B, then we can calculate the magnitude

$\frac{\Phi}{A}=B\ cos\theta$

3 0

2 years ago