Answer:
The heat gain of the room due to higher efficiency is 2.84 kW.
Explanation:
Given that,
Output power of shaft = 75 hp
Efficiency = 91%
High efficiency = 95.4%
We need to calculate the electric input given to motor
Using formula of efficiency




We need to calculate the electric input
For, heigh efficiency



The reduction of the heat gain of the room due to higher efficiency is

Put the value into the formula


Hence, The heat gain of the room due to higher efficiency is 2.84 kW.
The list of choices you provided with your question
is utterly devoid of any such examples.
Accelerating at 9.8 m/s² means that every second, the speed is 9.8 m/s faster than it was a second earlier. It's not important to the problem, but this number (9.8) happens to be the acceleration of gravity on Earth.
1% of the speed of light = (300,000,000 m/s) / 100 = 3,000,000 m/s .
Starting from zero speed, moving (9.8 m/s) faster every second,
how long does it take to reach 3,000,000 m/s ?
(3,000,000 m/s) / (9.8 m/s²) = 306,122 seconds .
(That's 5,102 minutes.)
(That's 85 hours.)
(That's 3.54 days.)
Speed at the beginning . . . zero .
Speed at the end . . . 3,000,000 m/s
Average speed . . . . . 1,500,000 m/s
Distance = (average speed) x (time)
= (1,500,000 m/s) x (306,122 sec) = 4.592 x 10¹¹ meters
= 459 million kilometers
That's like from Earth
to Sun
to Earth
to Sun.
Explanation:
a)Snell's law states that when light travels from a rarer to a denser substance, like air to water or from a less dense layer of the atmosphere to a denser layer, it bends towards the normal{an imaginary line that is perpendicular to the surface of both media}. However,the opposite occurs when light moves from a more dense to a less dense medium. The angle between the normal and the refracted light ray is known as the angle of refraction.
In case of earth as light from the stars enters the earth atmosphere it bends towards smaller angle because the earth density increases as the light travel towards the earth troposphere from the exosphere as per the Snell's law described above.
b)Light rays that travel straight down do not bend, while rays that enter the Earth's atmosphere at a shallower angle get refracted and bend towards the normal, roughly following the direction of the Earth's curvature.
This means that celestial objects in the zenith position directly above you appear in the correct position, while objects closer to the horizon appear to be higher up in the sky than they actually are.
It would be 0.25 meter or one fourth of a meter