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Marat540 [252]
3 years ago
8

A bus is moving at a speed of 150km/hr. Begins to slow at a constant rate of 3.0m/s each second. Find how far it goes before sto

pping
Physics
1 answer:
ladessa [460]3 years ago
4 0

Answer:

Distance = 13.9 meters

Explanation:

Given the following data;

Maximum speed = 150 km/hr to meters per seconds = 150 * 1000/3600 = 41.67 m/s

Decelerating speed = 3m/s

To find the distance travelled with this speed;

Distance = maximum speed/decelerating speed

Distance = 41.67/3

Distance = 13.9 meters

Therefore, the bus would travel a distance of 13.9 meters before stopping.

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A 1350 kg uniform boom is supported by a cable. The length of the boom is l. The cable is connected 1/4 the
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Answer:

Tension= 21,900N

Components of Normal force

Fnx= 17900N

Fny= 22700N

FN= 28900N

Explanation:

Tension in the cable is calculated by:

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FTorque(3/4L)= FBcostheta(1/2L)+ FWcostheta(L)

Ftorque=(Fcostheta(1/2L)+FWcosL)/(3/4L)

Ftorque= 2/3FBcostheta+ 4/3FWcostheta

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b) components of Normal force

Efx=FNx-FTcos(90-theta)=0 static equilibrium

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Fy=FNy+ FTsin(90-theta)-FB-FW=0

FNy= -FTsin(90-55)+FB+FW

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The Normal force

FN=sqrt(17900^2+22700^2)

FN= 28.900N

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3 years ago
I just need x isolated
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Answer:

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