The velocity of the brick is 39.2 m/s downward
Explanation:
The motion of the brick is a free fall motion, since the object is affected only by the force of gravity. Therefore, it has a uniformly accelerated motion towards the ground, with constant acceleration of
.
So, we can find its velocity using the suvat equation:

where
v is the final velocity
u is the initial velocity
a is the acceleration
t is the time
For the brick in this problem (taking downward as positive direction)
u = 0 (it is dropped from rest)

Therefore, its velocity after t = 4.0 s is:

Downward, because the sign is positive.
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Answer:

Explanation:
<u>Given:</u>
- Diameter of each disc, D = 2.4 cm.
- Distance between the discs, d = 1.0 mm.
- Charges on the discs, q = ±11 nC =

The surface area of each of the disc is given by

For the case, when d<<D, the strength of the electric field at a point due to a charged sheet is given by

<em>where</em>,
= surface charge density of the disc =
.
= electrical permittivity of free space = [tex\rm ]9\tiimes 10^9\ Nm^2/C^2[/tex].
The electric field strength between the discs due to negative disc is given by

Since, the electric field is directed from positive charge to negative charge, therefore, the direction of this electric field is towards the negative disc.
The electric field strength between the discs due to positive disc is given by

The direction of this electric field is away from the positive disc, i.e., towards negative disc.
The electric field between the discs due to both the disc is towards the negative disc, therefore the total electric field strength between the discs is given by
