Answer:
The price of 1 adult ticket is 12 dollars, and the price of a ticket for one student is 7 dollars
Step-by-step explanation:
Make a system of equations for the two days that the play was shown.
Let x = the price of an adult ticket
Let y = the price of a student ticket
For the first day:
<h3>9x+8y=164</h3>
For the second day:
<h3>2x+7y=73</h3>
Now, we can solve using the elimination method. Multiply the first equation by 2 and the second equation by 9. Then swap the order of the equations.
<h3>18x+63y= 657</h3><h3>-</h3><h3>18x+16y= 328</h3><h3>0x+ 47y= 329</h3><h3>divide both sides by 47</h3><h3>y = 7</h3><h3>Plug in 7 for y for the 2nd equation</h3><h3>2x+7(7)=73</h3><h3>2x+49=73</h3><h3>subtract 49 from both sides</h3><h3>2x= 24</h3><h3>divide both sides by 2</h3><h3>x = 12 </h3><h3>Check:</h3><h3>2(12)+7(7)=73</h3><h3>24+49= 73!</h3>
Answer:
You got this just keep trying
Step-by-step explanation:
Answer:
x = 7
Step-by-step explanation:
I hope this helps!
Answer:5
Step-by-step explanation:
If you look at the question in reverse you can backtrack your way through. Take 10 and instead of dividing, multiply it by 10, which is 60, add 6 instead of subtracting, which is 66, divide by 6 instead of multiplying, which is 11 and finally subtract 6 instead of adding, which is 5. Use five and try the question over to make sure you calculated correct.
Answer:
Children ticket cost $30 and adult ticket costs $40.
Step-by-step explanation:
Given that:
x = price of a child ticket
y = price of an adult ticket
According to given statement;
3x+2y=170 Eqn 1
4x+6y=360 Eqn 2
Multiplying Eqn 1 by 3
3(3x+2y=170)
9x+6y=510 Eqn 3
Subtracting Eqn 2 from Eqn 3
(9x+6y)-(4x+6y)=510-360
9x+6y-4x-6y=150
5x=150
Dividing both sides by 5

Putting x=30 in Eqn 1
3(30)+2y=170
90+2y=170
2y = 170-90
2y = 80
Dividing both sides by 2

Hence,
Children ticket cost $30 and adult ticket costs $40.