Keywords
quadratic equation, discriminant, complex roots, real roots
we know that
The formula to calculate the <u>roots</u> of the <u>quadratic equation</u> of the form 
is equal to
where
The <u>discriminant</u> of the <u>quadratic equation</u> is equal to
if 
----> the <u>quadratic equation</u> has two <u>real roots</u>
if 
----> the <u>quadratic equation</u> has one <u>real root</u>
if 
----> the <u>quadratic equation</u> has two <u>complex roots</u>
in this problem we have that
the <u>discriminant</u> is equal to 
so
the <u>quadratic equation</u> has two <u>complex roots</u>
therefore
the answer is the option A
There are two complex roots
9514 1404 393
Answer:
m = 2k/v
Step-by-step explanation:
Identify the coefficient of m (v/2) and multiply by its inverse (2/v).
(2/v)k = (2/v)m(v/2) . . . . multiply both sides of the equation by 2/v
2k/v = m . . . simplify
m = 2k/v
Answer: x=2
Step-by-step explanation:
2(5x+3)=26
Distribute the 2
10x+6=26
Subtract 6 from both sides
10x=20
Divide both sides by 10
x=2
Answer:
D
Step-by-step explanation:
27/12= 2.25
2.25*16=36
