Graph A shows a positive linear association between x and y.
F(x)=2x-10
y=2x-10
x=2y-10
x+10=2y-10+10 (add both sides by 10)
2y=x+10
2y/2=x+10/2 (divide both sides by 2)
y=1/2x+5
Final Answer: f^-1(x)=1/2x+5
Let f(x)=0, you'll get x=3 and x=-5, those are the x-intercepts of the function.
Answer:
Would ypu plz show us the number line so at least i could answer the question
Answer:
Y'=3xy-3x-12
Y'=F(-2,-1)=0
Step-by-step explanation:
The function of the equation at the point (-2,-1)
is where the equation make the function go to zero:
Y'=3xy-3x-12
Y'=F(-2,-1)=[3(-2)(-1)]-[3(-1)]-12
F(-2,-1)=[6]-[-6]-12
F(-2,-1)=6+6-12
F(-2,-1)=12-12
F(-2,-1)=0
Solving for y
3xy-3x-12=0
y=4/x+x
Making y=0



So the values make the function go to zero