Answer: pi/8
Step-by-step explanation:
adding or multiplying an irrational by a rational will result in another irrational. So we could take something like pi and divide it until it’s between 2/7 and 3/7. I did that and apparently pi/8 works, so boom
Vertex form:
y-k=a(x-h)^2
h=-2,k=-20,y=-12 when x=0
thus;
-12+20=a(0+2)^2
8=4a
a=2
Equation:
y+20=2(x+2)^2
y+20=2(x^2+4x+4)
f(x)=2(x^2+4x+4)-20
f(x)=2x^2+8x+8-20
f(x)=2x^2+8x-20
Answer:
Step-by-step explanation:
We are given the function:
And we want to finds its zeros.
Therefore:
Firstly, we can divide everything by -4:
Factor out an x:
This is in quadratic form. For simplicity, we can let:
Then by substitution:
Factor:
Substitute back:
By the Zero Product Property:
Solving for each case:
Therefore, our real and complex zeros are:
Answer:
Answer is 1
Explanation:
(-6 + 5) / (-2 + 1)
-1 / -1
1
Answer:
AHF = 105-42=63
Step-by-step explanation:
