1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
tester [92]
2 years ago
13

Two point charges are separated by a distance of 1 meter. How much would the force change if one charge was 4x larger?

Physics
2 answers:
nikklg [1K]2 years ago
8 0

Answer:

it would grow by 4x

Explanation:

jekas [21]2 years ago
6 0

Answer:

the force would increase 4 times more

Explanation

more force results more mass or acceleration

You might be interested in
What is the ocean floor made of?
Licemer1 [7]

Answer:

Oceanic crust is about 6 km (4 miles) thick. It is composed of several layers, not including the overlying sediment. The topmost layer, about 500 metres (1,650 feet) thick, includes lavas made of basalt (that is, rock material consisting largely of plagioclase [feldspar] and pyroxene).

Explanation:

it was on google hope  this helps

3 0
3 years ago
Which of these is most likely a characteristic of a parent isotope before it releases radioactive particles?
velikii [3]
The correct option is D.
Isotopic substances typically have unstable nuclei and that is why they disintegrate in order to become stable. During the process of disintegration, the nucleus of the unstable substance will be split into two smaller fragments, which are more stable that the parent isotope. This disintegration may also be accompanied by radiations.
8 0
3 years ago
Two students are sitting 1.50 m apart. One student has a mass of 70.0 kg and the other has a mass of 52.0 kg. What is the gravit
algol [13]

Answer:

The gravitational force between them is 1.079\times10^{-7}\ N.

Explanation:

Given that,

Distance = 1.50 m

Mass of one student = 70.0 kg

Mass of other student = 52.0 kg

We need to calculate the gravitational force

Using formula of gravitational force

F=\dfrac{Gm_{1}m_{2}}{r^2}

Where, m₁ = mass of one student

m₂ = mass of other studen

r = distance between them

Put the value into the formula

F=\dfrac{6.67\times10^{-11}\times70.0\times52.0}{1.50^2}

F=1.079\times10^{-7}\ N

Hence, The gravitational force between them is 1.079\times10^{-7}\ N.

5 0
3 years ago
A negative ion of charge -2e is located at the origin and a second negative ion of charge -3e is located nearby at x = 3.8 nm ,
Rus_ich [418]

Answer:

\vec{F}_{21}=-5.63\times 10^{-11}N\\\\\vec{F}_{21}=\\

Explanation:

Given that

Q_1 = -2e\, C\\\\Q_2=-3e\,C\\\\x= 3.8 \times 10^{-9}\,m\\\\y= 3.2 \times 10^{-9}\,m\\\\r=\sqrt{x^2+y^2}\\\\r= 4.96\times 10^{-9} m\\

As both charges are negative so there exist force of repulsion in direction as shown in figure.

F_{12}=\frac{kQ_1Q_2}{r^2}\\\\F_{12}= \frac{(9\times 10^9)(6)(1.602\times 10^{-19})^2}{(4.96\times 10^{-9})^2}\\\\F_{12}=5.63\times 10^{-11}N

Angle at which force F12 is acting is

\theta=tan^{-1}\frac{3.2}{3.8}\\\\\theta=tan^{-1}\frac{y}{x}\\\\\theta= 40.1^o

F_{x}=F_{12}cos\theta\\\\F_{x}=(5.63\times 10^{-11})cos(40.1)\\\\F_{x}=4.306\times 10^{-11}N\\\\F_{y}=F_{12}sin\theta\\\\F_{y}=(5.63\times 10^{-11})sin(40.1)\\\\F_{y}=3.62\times 10^{-11}N\\\\

\vec{F}_{12}=\vec{F}_{x}+\vec{F}_y\\\\\vec{F}_{12}=4.30\times 10^{-11}\,\hat{i} + 3.62\times 10^{-11}\,\hat{j}\\\\\vec{F}_{12}=

Force exerted on charge -2e is equal in magnitude to F12 but is in opposite direction

F_{21}=-5.63\times 10^{-11}N

\vec{F}_{21}=

7 0
3 years ago
The aqueduct passes under Johnson Road in Lancaster through a siphon. The maximum capacity of the aqueduct is 350 m3/s. The heig
Mariulka [41]

Answer:

D ≈ 8.45 m

L ≈ 100.02 m

Explanation:

Given

Q = 350 m³/s (volumetric water flow rate passing through the stretch of channel, maximum capacity of the aqueduct)

y₁ - y₂ = h = 2.00 m (the height difference from the upper to the lower channels)

x = 100.00 m (distance between the upper and the lower channels)

We assume that:

  • the upper and the lower channels are at the same pressure (the atmospheric pressure).
  • the velocity of water in the upper channel is zero (v₁ = 0 m/s).
  • y₁ = 2.00 m  (height of the upper channel)
  • y₂ = 0.00 m  (height of the lower channel)
  • g = 9.81 m/s²
  • ρ = 1000 Kg/m³ (density of water)

We apply Bernoulli's equation as follows between the point 1 (the upper channel) and the point 2 (the lower channel):

P₁ + (ρ*v₁²/2) + ρ*g*y₁ = P₂ + (ρ*v₂²/2) + ρ*g*y₂

Plugging the known values into the equation and simplifying we get

Patm + (1000 Kg/m³*(0 m/s)²/2) + (1000 Kg/m³)*(9.81 m/s²)*(2 m) = Patm + (1000 Kg/m³*v₂²/2) + (1000 Kg/m³)*(9.81 m/s²)*(0 m)

⇒ v₂ = 6.264 m/s

then we apply the formula

Q = v*A  ⇒   A = Q/v ⇒   A = Q/v₂

⇒   A = (350 m³/s)/(6.264 m/s)

⇒   A = 55.873 m²

then, we get the diameter of the pipe as follows

A = π*D²/4   ⇒   D = 2*√(A/π)

⇒   D = 2*√(55.873 m²/π)

⇒   D = 8.434 m ≈ 8.45 m

Now, the length of the pipe can be obtained as follows

L² = x² + h²

⇒ L² = (100.00 m)² + (2.00 m)²

⇒ L ≈ 100.02 m

6 0
2 years ago
Read 2 more answers
Other questions:
  • How are sound energy and light energy similar?
    8·2 answers
  • Give an example of something moving that is not accelerating
    15·1 answer
  • A fluorine atom has 7 valence electrons in its second shell.
    7·1 answer
  • Find the height of a baseball with a mass of 0.15 kg that has a GPE of 73.5 J.<br><br> Help please?
    14·2 answers
  • What is the average acceleration during the time interval 0 seconds to 10 seconds?
    12·1 answer
  • How are landslides and mudflows similar
    5·1 answer
  • Hurry. Answer quick!
    6·1 answer
  • Find the current through a 12 ohm resistive circuit when 24 volts is applied
    12·1 answer
  • PLS ANSWER DUE LATER TODAY!!!
    9·1 answer
  • Lou’s latest invention, aimed at urban dog owners, is the X-R-Leash. It is made of a rubber-like material that exerts a force Fx
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!