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a = (Vf - Vi)/t ; where distance d = [2(t)]/(4+t), t = 5secs, and Vi = 0
a = [(2t)/(4+t)]/t <---- working equation
a = {[2(5)]/9}/5 <---- cancel 5
a = 2/9 ft/s^2 <---- Answer
Midway between the two<span> solstices we have equinoxes – Vernal Equinox in March and </span>Autumnal Equinox<span> in September. ... After this time, the Earth's northern axis is tilted </span>more<span> and </span>more<span>towards ... Then on </span>Summer Solstice<span>, the Sun will reach its farthest north position in the sky</span>
Something stopped the force and was able to recreate the same amount of force to send it back to her. Example: A pole
Answer:
à in unit vector notation = 12.26485i + 7.54539j
B in unit vector notation = 16.3516i + 3.11529j
Explanation:
The detailed steps and calculation is shown in the attachment.
Answer:
A. 181.24 N
Explanation:
The magnitude of hte electrostatic force between two charged objects is given by the equation

where
k is the Coulomb's constant
q1, q2 are the magnitudes of the two charges
r is the separation between the charges
In this problem, we have:
is the magnitude of the 1st charge
is the magnitude of the 2nd charge
r = 2.5 cm = 0.025 m is the separation between the charges
Therefore, the magnitude of the electric force is:

So, the closest answer is
A) 181.24 N