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Sedbober [7]
2 years ago
7

A hole of 1 mm² is punched in a full 1-liter milk carton, 5 cm from the bottom. What is the initial speed of the outflow?

Physics
1 answer:
Oksanka [162]2 years ago
6 0
Use Bernoulli equation with the following assumptions.

1) velocity of the milk on the top is near 0, because the hole is so small that the level of milk will descend slowly, compared with the velocity of the outflow.

2) Pressure on the top = pressure on the bottom. This means that we consider that the top is open to the atmosphere.

Then, the terms of pressure cancel, and Bernoulli's equation leads to:

Z1 + p1/(d*g) + (V1)^2/(2g)  = Z2 + p2 /(d*g) + (V2)^2 /(2g)

=> (V2)^2 = 2g (Z1 - Z2)

g = 9.8 m/s^2

Z1 - Z2 = 5cm

(V2)^2 = 2*(9.8 m/s^2)*(0.05m) = 0.98 m^2/s^2

V2 = 0.99 m/s  


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(2) Friction forces acting opposite to the direction of motion.

(3) Normal force.

The forces acting on the person is balanced because the person is sliding with constant velocity.

From figure it is clear that, friction force is balanced by w\ sin\theta and normal is balanced by w\ cos\theta.

4 0
3 years ago
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Which of the following quantities provide enough information to calculate the tension in a string of mass per unit length μ that
Bad White [126]

Answer:

A. the wave speed v and Wavelength

Explanation:

Given that

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Frequency = f

The velocity V given as

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T=Tension

V=Velocity

V= f λ

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Therefore to find the tension ,only wavelength and speed is required.

The answer is A.

8 0
3 years ago
According to Newton's 3rd law of motion, if you hit a baseball with a bat it will _____.
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Fly in a straight line unless an outside force changes its course because i tried it once in a baseball game that my mommy rekt me in.
4 0
3 years ago
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(i). A ball of mass 1.500 kg is attached to the end of a cord 1.50 m long. The ball moves in a horizontal circle. If the cord ca
Aleks04 [339]

(a) Let v be the maximum linear speed with which the ball can move in a circle without breaking the cord. Its centripetal/radial acceleration has magnitude

a_{\rm rad} = \dfrac{v^2}R

where R is the radius of the circle.

The tension in the cord is what makes the ball move in its plane. By Newton's second law, the maximum net force on it is

F = (1.500\,\mathrm{kg}) a_{\rm rad}

so that

(1.500\,\mathrm{kg}) \dfrac{v^2}{1.50\,\rm m} = 64.0\,\mathrm N

Solve for v :

v^2 = \dfrac{(64.0\,\mathrm N)(1.50\,\mathrm m)}{1.500\,\rm kg} \\\\ \implies \boxed{v = 8.00 \dfrac{\rm m}{\rm s}}

(b) The net force equation in part (a) leads us to the relation

F = \dfrac{mv^2}R \implies v = \sqrt{\dfrac{FR}m}

so that v is directly proportional to the square root of R. As the radius R increases, the maximum linear speed v will also increase, so the cord is less likely to break if we keep up the same speed.

6 0
1 year ago
Please help!!!
Lubov Fominskaja [6]

question: Please help!!!

If a bottle is being squeezed with a force of 10 Newtons and the area of the bottle is 15

squared inches. What is the pressure??

Answer:

1025.64 N/m²

Explanation:

Pressure: This can be defined as the ratio of force to area. The si unit of pressure is N/m².

From the question,

P = F/A........................ Equation 1

Where F = Force, A = Area.

Given: F = 10 Newtons, A = 15 Squared Inches = (15×0.00065) = 0.00975 m²

Substitute these values into equation 1

P = 10/0.00975

P = 1025.64 N/m²

Hence the pressure of the bottle is 1025.64 N/m²

5 0
3 years ago
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