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Dennis_Churaev [7]
3 years ago
8

A microwave oven uses 1,200 watts. It runs a total of 6 hours during the corse of a week. How much energy does the microwave ove

n use during the week?? a 4.8 kilowatt-hours. b 5.0 kilowatt-hours. c 7.2 kilowatt-hours. d 6.5 kilowatt-hours.
Physics
1 answer:
zzz [600]3 years ago
5 0

Answer:

7.2 kilowatts

Explanation:

Energy= power x time

where:

power = 1,200watts to kilowatts is 1.2kw

time = 6hours

therefore,

energy = 1.2kw x 6hrs

=7.2 kilowatts

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A railroad freight car, mass 15,000 kg, is allowed to coast along a level track at a speed of 2.0 m/s. It collides and couples w
gayaneshka [121]

Answer:

The speed of the two cars after coupling is 0.46 m/s.

Explanation:

It is given that,

Mass of car 1, m₁ = 15,000 kg

Mass of car 2, m₂ = 50,000 kg

Speed of car 1, u₁ = 2 m/s

Initial speed of car 2, u₂ = 0

Let V is the speed of the two cars after coupling. It is the case of inelastic collision. Applying the conservation of momentum as :

m_1u_1+m_2u_2=(m_1+m_2)V

V=\dfrac{m_1u_1+m_2u_2}{(m_1+m_2)}

V=\dfrac{15000\ kg\times 2\ m/s+0}{(15000\ kg+50000\ kg)}  

V = 0.46 m/s

So, the speed of the two cars after coupling is 0.46 m/s. Hence, this is the required solution.          

3 0
3 years ago
An electromagnetic wave of wavelength 435 nm is traveling in vacuum in the —z direction. The electric field has an amplitude of
Aloiza [94]

Answer:

a) 6.9*10^14 Hz

b) 9*10^-12 T

Explanation:

From the question, we know that

435 nm is given as the wavelength of the wave, at the same time, we also know that the amplitude of the electric field, E(max) has been given to be 2.7*10^-3 V/m

a)

To find the frequency of the wave, we would be applying this formula

c = fλ, where c = speed of light

f = c/λ

f = 3*10^8 / 435*10^-9

f = 6.90*10^14 Hz

b) again, to find the amplitude of the magnetic field, we would use this relation

E(max) = B(max) * c, magnetic field amplitude, B(max) =

B(max) = E(max)/c

B(max) = 2.7*10^-3 / 3*10^8

B(max) = 9*10^-12 T

c) and lastly,

1T = 1 (V.s/m^2)

6 0
3 years ago
This process releases a large amount of . Energy ,oxygen ,or water
EleoNora [17]

Answer:

carbon dioxide i think please be right

4 0
3 years ago
Consider a wet banked roadway, where there is a coefficient of static friction of 0.30 and a coefficient of kinetic friction of
gulaghasi [49]

Answer:

a) v = 20.9 m/s

b) v = 8.46 m/s

Explanation:

Given:-

- The coefficient of static friction is us = 0.30

- The coefficient of static friction is uk= 0.25

- The radius of the curve R = 50m

- The bank Angle β = 25

Find:-

a) If the banking angle is β=25∘, what is the maximum speed the automobile can have before sliding up the banking?  

b) What is the minimum speed the automobile can have before sliding down the banking?

Solution:-

- We will investigate the sliding-up case first. Develop a FBD as given in (attachment).

- Use Newton's second law of motion vertical to slope of bank where the car is in equilibrium:

                       Sum ( F_n ) = 0

                       N*cos(β) - m*g - Ff*sin(β) = 0

Where,            Frictional Force Ff = us*N

                      N (cos(β) - us*sin(β)) = mg   ... Eq 1

- Use Newton's second law of motion horizontal to slope of bank where the car is accelerating:

                       Sum ( F_h ) = m*a

                       Ff*cos(β) + Nsin(β) = m*v^2 / R

                       N (us*cos (β) + sin (β) ) = m*v^2 / R  .... Eq 2

- Divide the two equations:

                    v^2 / gR = [ us*cos (β) + sin (β) ] / [ cos (β) - us*sin (β) ]

                    v^2 = [ 0.25*cos (25) + sin (25) ]*9.81*50 / [ cos (25) - 0.25*sin (25) ]

                    v = 20.9 m/s

- For the slip down case. We have, friction force Ff reversed hence us = -us. Then the v can be given as:

                    v^2 / gR = [ -us*cos (β) + sin (β) ] / [ cos (β) + us*sin (β) ]

                    v^2 = [ -0.25*cos (25) + sin (25) ]*9.81*50 / [ cos (25) + 0.25*sin (25) ]

                    v = 8.46 m/s

6 0
3 years ago
Which form of carbon in the figure above is the hardest
kaheart [24]
There are no hard forms of anything depicted above.

Diamond is the hardest form of carbon.
3 0
3 years ago
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