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3 years ago

What are all the roots of the equation x^2+6x-9

Mathematics

1 answer:

frez [133]3 years ago

5 0

Answer:

x = - 3 ± 3 $\sqrt{2}$

Step-by-step explanation:

given the equation x² + 6x - 9 = 0

We can solve for x using the quadratic formula

x = ( - b ± $\sqrt{b^2-4ac }$ ) / 2a

with a = 1, b = 6 and c = - 9

x = ( - 6 ± $\sqrt{6^2-(4(1)(-9)}$ ) / 2

= ( - 6 ± $\sqrt{36+36}$ ) / 2

= ( - 6 ± $\sqrt{72}$ ) / 2

= ( - 6 ± 6 $\sqrt{2}$ ) / 2

x = - 3 ± 3 $\sqrt{2}$

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9.1 x 10-31 kg.

Reptile [31]

1 electron has a mass of 9.1 X 10-31 kg. How many electrons n does it take to make 1 kg?

(1 e)/(9.1 X 10-31 kg) = n/(1 kg)

So, n = 1.10 X 1030 electrons

Each electron has a charge of 1.6 X 10-19 C, where C stands for Coulombs. So, the n electrons have a charge of q = ne = (1.10 X 1030 electrons) X (1.6 X 10-19 C/electron) = 1.76 X 1011 C.

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2 years ago

Solve 1 5/7 • x for x = 5/6

VARVARA [1.3K]

Answer:

1 3/7

Step-by-step explanation:

1 5/7 * 5/6

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2/7 * 5/1

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5 0

3 years ago

Read 2 more answers

Need help simplifying this

diamong [38]

The simplified answer is $\frac{\left(12 x^{2}+7 x y-4 y z-3 x z+3 y^{2}\right)}{6 x^{2}+3 x z+2 x y+y z}$ .

<u>Step-by-step explanation:</u>

$$\frac{3 y+2 x}{z+2 x}-\frac{2 y-3 x}{3 x+y}-\frac{2 z(y+3 x)}{6 x^{2}+3 x z+2 x y+y z}$

To add or subtract denominators of the fraction must be same.

If it is not the same, we must take LCM of the denominators. and so we can add the fractions.

To make the denominator same multiply the 1st term $(\frac{3x+y}{3x+y})$ and 2nd term by $(\frac{z+2x}{z+2x})$

= $\frac{(3 y+2 x)(3 x+y)}{(z+2 x)(3 x+y)}-\frac{(2 y-3 x)(z+2 x)}{(3 x+y)(z+2 x)}-\frac{2 z(y+3 x)}{6 x^{2}+3 x z+2 x y+y z}$

LCM of the denominators is 6x²+ 3xz + 2xy +yz.

Multiply the factors in the numerator.

= $\frac{\left(6 x^{2}+3 y^{2}+11 x y\right)}{(z+2 x)(3 x+y)}-\frac{\left(2 y z+4 x y-3 x z-6 x^{2}\right)}{(3 x+y)(z+2 x)}-\frac{2 z y+6 x z}{6 x^{2}+3 x z+2 x y+y z}$

Now, the denominators are same, you can subtract it.

= $\frac{\left(6 x^{2}+6 x^{2}+11 x y-4 x y-2 y z-2 y z+3 x z-6 x z+3 y^{2}\right)}{6 x^{2}+3 x z+2 x y+y z}$

= $\frac{\left(12 x^{2}+7 x y-4 y z-3 x z+3 y^{2}\right)}{6 x^{2}+3 x z+2 x y+y z}$

Thus the simplified solution is $\frac{\left(12 x^{2}+7 x y-4 y z-3 x z+3 y^{2}\right)}{6 x^{2}+3 x z+2 x y+y z}$

4 0

3 years ago

The ratio of girls to boys in 6th grade is 3:4. If there are 182 6th graders, how many are girls

nataly862011 [7]

Answer:

78 girls

Step-by-step explanation:

Ratio is 3:4, so that means the total number of 182 can be divided into 7 parts. 182 divided by 7 is 26, so each part is 26. The ratio of girls is 3, so 3 times 26 is 78. You can check this by putting (3*26)/(4*26) simplifies to 78/104 to 3/4 which is the right ratio

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3 years ago

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tigry1 [53]

Answer:

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3 years ago