Question

What are all the roots of the equation x^2+6x-9

Answer 1

Answer:

x = - 3 ± 3$\sqrt{2}$

Step-by-step explanation:

given the equation x² + 6x - 9 = 0

We can solve for x using the quadratic formula

x = ( - b ± $\sqrt{b^2-4ac }$ ) / 2a

with a = 1, b = 6 and c = - 9

x = ( - 6 ± $\sqrt{6^2-(4(1)(-9)}$ ) / 2

  = ( - 6 ± $\sqrt{36+36}$ ) / 2

  = ( - 6 ± $\sqrt{72}$ ) / 2

  = ( - 6 ± 6$\sqrt{2}$ ) / 2

x = - 3 ± 3$\sqrt{2}$