What are all the roots of the equation x^2+6x-9
1 answer:
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Assuming the shape of the room is a rectangle :
Area = Width x Length.
Let's call width "w" and length "l" . Now if, the width is 4/5 of the length that means 4/5 times length gives us the width, like this :
As given in the question, area of the rectangle is 320 square feet. And as I said before area of a rectangle can be found by multiplying its length and width.
, we can plug w's value in the previous equation to find "l".
Let's plug "l"s value in the equation.
The length is 20 feet and the width is 16 feet.
Area = Width x Length.
Let's call width "w" and length "l" . Now if, the width is 4/5 of the length that means 4/5 times length gives us the width, like this :
As given in the question, area of the rectangle is 320 square feet. And as I said before area of a rectangle can be found by multiplying its length and width.
Let's plug "l"s value in the equation.
The length is 20 feet and the width is 16 feet.