The roller coaster from problem #1 then tops a second hill at 15.0 m/s, how high is the second hill?
1 answer:
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Till the time car is just adjacent to the bicycle we can say
distance moved by cycle = distance moved by car
Time taken by car to accelerate from rest
Time taken by cycle to accelerate
now the distance moved by cycle in time "t"
distance moved by car in same time
now make them equal
so cycle will move ahead of car for t = 5.68 s
Answer:
ω₂ = 1.9025 x 10⁻⁶ rad/s
Explanation:
given,
mass of star = 1.61 x 10³¹ kg
angular velocity = 1.60 x 10⁻⁷ rad/s
diameter suddenly shrinks = 0.29 x present size
r₂ = 0.29 r₁
using conservation of angular momentum
I₁ ω₁ = I₂ ω₂
ω₂ = 1.9025 x 10⁻⁶ rad/s