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3 years ago

Which causes the thermocline?

Physics

2 answers:

scoundrel [369]3 years ago

7 0

Hello,

The correct answer is C) The sun's radiation does not extend below a certain depth; therefore, deeper ocean water is colder than surface water.

<em>Hope this helps!!!! :)</em>

<em>**(</em><em>Vanessa</em><em>)**</em>

<em />

Igoryamba3 years ago

4 0

<span>Thermocline is a layer between warm water from the ocean’s surface and cool water from below the ocean. In here, the temperature decreases rapidly from the warmer layer to the colder layer. A thermocline forms due to the heat of the sun heating the ocean’s surface. Because of the difference in density between warm and cooler ocean water, cooler ocean water sinks and warmer ocean water floats. This is caused due to the heat and mass transfer between particles of the ocean. The answer is letter C. The sun’s radiation does not extend below a certain depth; therefore, deeper ocean water is colder than surface water.</span>

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Energy of position or location is called

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The answer is B!
Explanation: Energy stored in an object due to its position is Potential Energy. · Energy that a moving object has due to its motion is Kinetic Energy.

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3 years ago

Standing on the surface of the earth you have a weight of 100 N. If you were to travel until you were 2

Vika [28.1K]

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2 years ago

Samantha is refinishing her rusty wheelbarrow. She moves her sandpaper back and forth 45 times over a rusty area, each time movi

Leviafan [203]

Answer:

W = 12.96 J

Explanation:

The force acting in the direction of motion of the sand paper is the frictional force. So, we first calculate the frictional force:

F = μR

where,

F = Friction Force = ?

μ = 0.92

R = Normal Force = 2.6 N

Therefore,

F = (0.92)(2.6 N)

F = 2.4 N

Now, the displacement is given as:

d = (0.12 m)(45)

d = 5.4 m

So, the work done will be:

W = F d

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3 years ago

Question 4 What would be the UCS for Tab the dog? O The shock O The flowers and fence O Fear O The boundary Question 5

Harrizon [31]

The unconditioned stimulus (UCS) for Tab the dog is: B. The flowers and fence.

<h3>The types of stimuli.</h3>

In Science, the two (2) stimuli that are repeatedly paired in classical conditioning include:

Conditioned stimulus

Unconditioned stimulus

<h3>What is an unconditioned stimulus?</h3>

An unconditioned stimulus can be defined as a stimulus that is capable of naturally triggering a response, before or without any conditioning while it elicit a specific response without learning.

This ultimately implies that, an unconditioned stimulus leads to an automatic response in a living organism such as a dog.

In this scenario, the unconditioned stimulus (UCS) for Tab the dog is simply the flowers and fence.

Read more on unconditioned stimulus here: brainly.com/question/24868138

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2 years ago

Steel is very stiff, and the Young's modulus for steel is unusually large, 2.0×1011 N/m2. A cube of steel 25 cm on a side suppor

TEA [102]

Answer:

Force (normal) = 833.85 N Compression = 1.67 x 10⁻⁸ m

Explanation:

Given data Young's Modulus (Y) = 2 x 10¹¹ N/m², Length of one side of cube = 25 cm = 0.25 m, mass of load = 85 kg

Normal force is the force exerted upon an object that is in contact with another stable object. This force would be applied by the surface onto the object in the same vector and is used to keep the object stable while it rests on a surface.

We know from Newton's Second Law that

F = ma where m is the mass and a is the acceleration (<em>in this case due to gravity</em>) hence, the normal opposing force to the load applied by the surface would be equal to the force applied on the surface by the weight of the load on the surface, So

F (normal) = M (load) x a = 85 x 9.81 = 833.85 N

Compression is the change in length of an object by the exertion of force upon it. Using the Young's Modulus formula we can find this change in the cube of steel. The Young's Modulus is given by

Y = (F/A)/(ΔL/L), where Y is the Young's Modulus, F is the Force being applied on the object, A is the cross sectional area on which the said force is applied, ΔL is the change in length due to said force being applied and L is the original Length of the side of the cross sectional area.

Solving this for ΔL, we can re- arrange the equation

ΔL = (F x L)/(Y x A) since area of square is L x L we can simplify the equation to get

ΔL = (F)/(Y x L), substitute the values

ΔL = (833.85)/(2 x 10¹¹ x 0.25) = 1.67 x 10⁻⁸m

6 0

3 years ago