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4 years ago

Yesterday you rented 4 movies. You watched 3 of them. Which choice correctly represents the movies you watched?

Mathematics

1 answer:

TEA [102]4 years ago

5 0

Choice A. 75%. 1\4 is equal to 25%. 2\4 is equal to 50%. 3\4 is equal to 75%. 4/4 is equal to 100%

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A crew has paved 3/4 of a mile of road. If they have completed 50% of the work, how long is the road they are paving?

Sonja [21]

1 1/2 miles is indeed your answer because if 50% of the road is done which was 3/4 of a mile just add another 3/4 of a mile if it’s 50% (50% +50%=100%)

7 0

3 years ago

This is a example ^^^

marshall27 [118]

Answer:

Step-by-step explanation:

It is a right triangle as it has a right angle (you can draw a little square to show that).

It's side are already recorded, so I tried my best, though I'm not sure it's correct.

Hope that helps!

4 0

3 years ago

YALLL PLEASE HELP MEEEEE

Anit [1.1K]

Answer:1

Step-by-step explanation:

7 0

3 years ago

In parallelogram EFGH, EJ = 6x + 3 and JG = 10x - 5 What is EG? A: 15 B: 12 C: 25 D: 30

Ne4ueva [31]

Answer:

D. 30

Step-by-step explanation:

It seems J is the intersection of diagonals.

We know diagonals of the parallelogram bisect each other.

It gives us:

EG = EJ + JG and
EJ = JG

Substitute and solve for x:

6x + 3 = 10x - 5
10x - 6x = 3 + 5
4x = 8
x = 2

Find the value of EJ:

EJ = 6*2 + 3 = 15

Find the value of EG:

EG = 2*EJ = 2*15 = 30

Correct choice is D

5 0

3 years ago

Read 2 more answers

in a certain game, a fair die is rolled and a player gains 20 points if the die shows a 6. if the die does not show a 6, the pla

BaLLatris [955]

The expected gain or loss is an illustration of mean and expected values.

The expected total gain is 83 points

The given parameters are:

Addition of 20 points for rolling a 6
Removal of 3 points for not rolling a 6

The probability of rolling a 6 in a fair die is 1/6.

The probability of not rolling a 6 in a fair die is 5/6.

So, the expected gain in each game is:

$\mathbf{E(x) = 20 \times \frac 16 - 3 \times \frac 56}$

$\mathbf{E(x) = \frac{20}6 - \frac{15}6}$

Take LCM

$\mathbf{E(x) = \frac{5}6}$

$\mathbf{E(x) = 0.83}$

The number of games is 100.

So, the expected gain is:

$\mathbf{Gain = 100 \times 0.83}$

$\mathbf{Gain = 83}$

Hence, the expected total gain is 83 points