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Alex_Xolod [135]
2 years ago
6

!! Need help with the problem in the photo. !!

Mathematics
2 answers:
suter [353]2 years ago
5 0

Answer:

whats c?

Step-by-step explanation:

Dominik [7]2 years ago
4 0

it doesnt show all the answer choices

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For the pair of functions, find the indicated sum, difference, product, or quotient. f(x) = 16 - x2; g(x) = 4 - x Find (f + g)(x
Rudik [331]
(16-x²)+(4-x) or (-x²+16)+(-x+4)

Combine like terms

(-x²+20-x) or (-x²-x+20)
7 0
3 years ago
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I need help I don’t understand...
pentagon [3]

Answer:

(1 , -2)

Step-by-step explanation:

The intersecting point of two lines is the solution

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2 years ago
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Plz help meeeee plz
Sauron [17]

Answer:

Less than

Step-by-step explanation:

Its less than because the angle of LS is 98 while MS is 95, so LS is longer

3 0
2 years ago
For every 5 pages in a book Fred reads, Lonnie reads 4 pages. In 1 hour, they read a combined total of 36 pages. How many pages
nydimaria [60]

Answer:

Hence the number of pages read by Lonnie is 16 pages when they read a combined of 36 pages.

Step-by-step explanation:

The table that can be formed by the rate at which they study the number of pages of a book is:

Fred     Lonnie       total

 5           4                9

 10          8               18

 15          12              27

 20         16              36

That means when they read a combined of 36 pages.

Then the number of pages read by Fred is 20 pages.

and the number of pages read by Lonnie is 16 pages.

(

Also it could be done as :

Let Fred reads 'x' pages.

so, the number of pages read by Lonnie is: (4/5)x

Hence,

x+(4/5)x=36

on solving this linear equation we have:

x=20

and (4/5)x=16

)

Hence the number of pages read by Lonnie is 16 pages when they read a combined of 36 pages.

3 0
3 years ago
Suppose that two teams play a series of games that ends when one of them has won ???? games. Also suppose that each game played
Musya8 [376]

Answer:

(a) E(X) = -2p² + 2p + 2; d²/dp² E(X) at p = 1/2 is less than 0

(b) 6p⁴ - 12p³ + 3p² + 3p + 3; d²/dp² E(X) at p = 1/2 is less than 0

Step-by-step explanation:

(a) when i = 2, the expected number of played games will be:

E(X) = 2[p² + (1-p)²] + 3[2p² (1-p) + 2p(1-p)²] = 2[p²+1-2p+p²] + 3[2p²-2p³+2p(1-2p+p²)] = 2[2p²-2p+1] + 3[2p² - 2p³+2p-4p²+2p³] =  4p²-4p+2-6p²+6p = -2p²+2p+2.

If p = 1/2, then:

d²/dp² E(X) = d/dp (-4p + 2) = -4 which is less than 0. Therefore, the E(X) is maximized.

(b) when i = 3;

E(X) = 3[p³ + (1-p)³] + 4[3p³(1-p) + 3p(1-p)³] + 5[6p³(1-p)² + 6p²(1-p)³]

Simplification and rearrangement lead to:

E(X) = 6p⁴-12p³+3p²+3p+3

if p = 1/2, then:

d²/dp² E(X) at p = 1/2 = d/dp (24p³-36p²+6p+3) = 72p²-72p+6 = 72(1/2)² - 72(1/2) +6 = 18 - 36 +8 = -10

Therefore, E(X) is maximized.

6 0
2 years ago
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