Answer:
The volume of the 50% solution used is 0.8 gallons and the volume of 25% solution used is 1.2 gallons.
Explanation:
Let the volume of the 50% solution be be x gallons.
Let the volume of 25% solution be y gallons.
Total volume of the solution after mixing above volumes of the solutions = 2 gallons
x gal + y gal = 2 gal
...[1]
Percentage of the final salt solution = 35%
....[2]
On solving [1] and [2] , we get:
x = 0.8 , y = 1.2
So, the volume of the 50% solution used is 0.8 gallons and the volume of 25% solution used is 1.2 gallons.
The volume is 12 mL (0.012 L)
Before the aluminum was added, the water reached 132mL. After it was added, it reached 144. That means the Aluminum takes up (144-132)= 12mL of space.
The density = mass/volume. If the aluminum bar has a mass of 78g and volume of 0.012L, 78/0.012=6,500 g/L
<span>[Cu(NH3)4]2+ forms a blue solution. When concentrated HCl is added to this solution, what color will the solution change to yellow.
Reason:
When conc. HCl is added to the solution containing </span>[Cu(NH3)4]2+, Cl- ions will replace NH3 and form [Cu(Cl)4]2- complex. This can be understood for the following reaction:
[Cu(NH3)4]2+ + Cl- ↔ [Cu(Cl)4]2- + NH3
The Cl- ion is a weak field ligand, while NH3 is a strong field ligand. Hence, Cl- will in less splitting of d-orbitals, as compared to NH3. Due to this, photons of different energies will be absorbed by these complexes, and hence they display different colours.
Answer:
2.8087*10^-12 kJ per mole of reaction (2.8087*10^-12 kJ/mol).
Explanation:
To calculate the energy produced, we need to write a balanced equation for the reaction and determine the change in the masses of the reactants and products. Afterward, we can use the energy equation to determine the energy produced. The balanced equation for the nuclear reaction is shown below:
³₁H + ²₁H ⇒⁴₂He + ¹₀n
The masses of atoms are ³₁H is 3.01605 amu, ²₁H is 2.0140 amu, ⁴₂He is 4.00260 amu, and ¹₀n is 1.008665 amu.
change in mass Δm = (3.01605+2.0140) - (4.00260+1.008665) = 0.0188 amu
Energy produced, E = m*C^2
C is the speed of light = 3*10^8 m/s and 1 amu = 1.66*10^-27 kg
Therefore:
E = 0.0188*1.66*10^-27 * (3*10^8)^2 = 2.8087*10^-12 kJ per mole of reaction.
Therefore, in scientific notation, the energy released is 2.8087*10^-12 kJ/mol
