Reaction: 2K₍s₎ + 2H₂O₍l₎ → 2KOH₍aq₎ + H₂₍g₎.
K - potassium.
H₂O - water.
KOH - potassium-hydroxide.
H₂ - hydrogen.
s - solid phase.
l - liquid.
aq - disolves in water.
g - gas.
Reaction is exothermal (release of energy) and potassium burns a purple flame. H<span>ydrogen released during the reaction reacts with </span>oxygen<span> and ignites.</span><span>
</span>
Explanation:
It is known that the value of Avogadro's number is 
.
Therefore, calculate moles of gold atoms as follows.
Moles of gold atom = 
= 
= 
mol
= 1.99 mol
Thus, we can conclude that 1.99 mol of gold atoms are equivalent to 
atoms.
Answer:
1-Find the molar mass of the substance.
2-H3PO4
3-New atoms are created.
4-The ratios of the number of moles of each substance that react and that are produced.
5-conservation of mass
6-The number of atoms for every element is equal on both sides of the equation.
7-1:1
8-1:03
9-5.50%
Answer:
8.324 g
Explanation:
First we <u>convert 750.0 mL into L</u>:
- 750.0 mL / 1000 = 0.750 L
Then we <u>calculate the required number of moles of CaCl₂</u>, using the <em>definition of molarity</em>:
- Molarity = moles / liters
- Molarity * liters = moles
- 0.100 M * 0.750 L = 0.075 mol
Finally we <u>convert 0.075 moles of CaCl₂ into grams</u>, using its <em>molar mass</em>:
- 0.075 mol * 110.98 g/mol = 8.324 g
An ionic compound is always an electrolyte
