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bixtya [17]
3 years ago
14

The molar heat of vaporization for water is 10.79 kJ/mol. How much energy must be absorbed by 100 grams

Chemistry
1 answer:
lara [203]3 years ago
3 0
<h3>Answer:</h3>

59.878 Kilo joules

<h3>Explanation:</h3>

We are given;

  • Molar heat of vaporization for water as 10.79 kJ/mol
  • Mass of water 100 grams

We are required to calculate the amount of energy absorbed to convert water to ice.

  • We need to know that the process of conversion of water to steam without change in temperature is known as vaporization or boiling.
  • Therefore, heat absorbed is calculated by multiplying the mass of water or the number of moles by heat of vaporization.
  • That is, Q = m × ΔHf
  • When given the number of moles and the molar heat of vaporization, then Q = n × ΔHf

In this case;

Mass of water = 100 g

But, molar mass of water = 18.02 g/mol

Moles of water = 100 g ÷ 18.02 g/mol

                         = 5.549 Moles

Therefore;

Q = 5.549 moles × 10.79 kJ/mol

   = 59.878 Kilo joules

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