Answer:
the empirical formula of the metal fluoride.
Explanation:
Mass of copper heated = 8.249 g
Mass of copper fluoride formed = 13.18 g
Mass of fluorine gas in copper fluoride = x
Moles of copper :
Moles of fluorine:
For the empirical formula divide the smallest mole of an element with all the moles of elements present in the compound.
The empirical formula of the copper fluoride =
the empirical formula of the metal fluoride.
Isotopes of an element will contain the same number of protons and electrons but will differ in the number of neutrons they contain. In other words, isotopes have the same atomic number because they are the same element but have a different atomic mass because they contain a different number of neutrons.
0.555 = 1.90/V
⇒ V = 1.90/0.555
⇒ V = 3.423 liter
