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mariarad [96]
3 years ago
14

[cu(nh3)4]2 forms a blue solution. when concentrated hcl is added to this solution, what color will the solution change to

Chemistry
2 answers:
g100num [7]3 years ago
8 0
<span>[Cu(NH3)4]2+ forms a blue solution. When concentrated HCl is added to this solution, what color will the solution change to yellow.

Reason: 
When conc. HCl is added to the solution containing </span>[Cu(NH3)4]2+, Cl- ions will replace NH3 and form [Cu(Cl)4]2- complex. This can be understood for the following reaction:

[Cu(NH3)4]2+     +          Cl-          ↔         [Cu(Cl)4]2-      +        NH3

The Cl- ion is a weak field ligand, while NH3 is a strong field ligand. Hence, Cl- will in less splitting of d-orbitals, as compared to NH3. Due to this, photons of different energies will be absorbed by these complexes, and hence they display different colours.
Ainat [17]3 years ago
8 0

Answer:

Green.

Explanation:

Hello,

The tetra amine copper (II) cation is naturally blue due to the presence of copper and nitrogen into the solution. On the other hand, when chloride anions are added due to the hydrochloric acid addition, the formed species is [Cu(Cl)_4]^{-2} whose color is green which is characteristic for copper and chlorine based salts (for example cupric chloride).

Best regards.

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Tems11 [23]

Answer:56.98496

Explanation:

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7 0
3 years ago
Would the calculated molar mass be higher, lower, or the same as the actual molar mass of the compound if the unknown contained
Delicious77 [7]

Answer:

higher

Explanation:

If it contains a impurity that is insoluble it won't dissolve completely, the solution would be smaller than it is supposed to be, when compared to a compound without such insoluble impurity. Molecular weight determination won't be accurate because the molecular weight obtained will be higher as a result of the fact that the mass of the solute would include the actual solute that is changing the temperature and the excess mass of the impurity.

3 0
2 years ago
A woman is brought into the emergency room experiencing nausea and vomiting. She is also hyperventilating. She says that she ing
Keith_Richards [23]

Answer:

Protonated form: 96.87%

Unprotonated form: 3.13%

Explanation:

To find the percentage of protoned and unprotoned forms of salicylic acid we must use Henderson-Hasselbalch equation:

pH = pKa + log [A⁻] / [HA]

<em>Where pKa of salicylic acid is 3.49; [A⁻] is the unprotonated form and [HA]:</em>

<em />

2.0 = 3.49 + log [A⁻] / [HA]

0.03236 = [A⁻] / [HA] <em>(1)</em>

And as:

[A⁻] + [HA] = 100% <em>(2)</em>

<em></em>

Replacing (2) in (1):

0.03236 = 100 - [HA] / [HA]

0.03236 [HA] = 100 - [HA]

1.03236[HA] = 100

<h3>[HA] = 96.87%</h3>

And [A⁻]:

[A⁻] = 100 - 96.87

<h3>[A⁻] = 3.13%</h3>

<em></em>

3 0
2 years ago
Fe2o3(s)+3co(g)→2fe(s)+3co2(g) in a reaction mixture containing 189 g fe2o3 and 63.0 g co, co is the limiting reactant. part a c
vfiekz [6]
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The answer would be A, a rotation.
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