Magnesium Peroxydisulphate with formula of MgS₂O₈.
<h3><u>Explanation:</u></h3>
The question clearly stands on the concept of molarity and atomic weights.
The atomic weight of magnesium = 24.
The atomic weight of sulphur = 32.
The atomic weight of oxygen = 16.
The amount of magnesium present = 0.248 g
The amount of sulphur present = 0.665 g.
The amount of oxygen present = 1.31g.
So, moles of magnesium present = 0.01 moles.
Moles of sulphur present = 0.02 moles.
Moles of oxygen present = 0.08 moles.
So, mole ratio of the compound as magnesium : sulphur : oxygen = 1:2:8.
So the compound is Magnesium Peroxydisulphate with formula of MgS₂O₈.
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The molarity of the stock Mn²⁺ ions is 0.0288 M
Based on the dilution formula;
- The molarity of A is 0.00144 M
- The molarity of B is 0.0000576 M
- The molarity of C is 0.000001152 M
<h3>What is the molarity of a solution?</h3>
The molarity of a solution is the number of moles of a solute dissolved in a given volume of solution in liters.
- Molarity = number of moles/volume
The molarity of the stock solution is:
moles of Mn²⁺ ions = mass / molar mass
molar mass of Mn²⁺ ions = 55.0 g/mol
moles of Mn²⁺ ions = 1.584 / 55
moles of Mn²⁺ ions = 0.0288 moles
molarity of Mn²⁺ ions = 0.0288 / 1
molarity of Mn²⁺ ions = 0.0288 M
The dilution formula is used to determine the molarities of A, B, and C.
C₁V₁ = C₂V₂
C₂ = C₁V₁ / V₂
Where;
- C₁ = initial molarity
- V₁ = initial volume
- C₂ = final molarity
- V₂ = final volume
Molarity of A = 50 * 0.0288 / 1000
Molarity of A = 0.00144 M
Molarity of B = 10 * 0.00144 / 250
Molarity of B = 0.0000576 M
Molarity of C = 10 * 0.0000576 / 500
Molarity of C = 0.000001152 M
Learn more about molarity at: brainly.com/question/17138838
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Answer:
Hence option C is correct.
Explanation:
the process is osmosis a process by which molecules of a solvent tend to pass through a semipermeable membrane from a less concentrated solution into a more concentrated one.
so the answer for the this question will be There is a net flow of water from the 4% starch solution into the 10% starch solution because solvent (water) moving from low conc. (4 %) to high conc. (10%)
Hence option C is correct.
Answer:
Rate = 116m⁻¹s⁻¹[lactose][H]⁺
Explanation:
the formula for rate of reaction is given as
Rate = k[lactose]∧α[H]⁺∧β
we solve for the value of α and β
([lactose]₁/[lactose]₂)∧α
α = 
when we divide this equation
α = 
α = 1
we find β
R₁/R₂ = 0.01/0.02(0.001/0.001)∧β
0.00116/0.00232 = 0.5(1)∧β
β = 1
Rate = k[lactose]∧α[H]⁺∧β
we have to find the value for k
k = 0.00116/0.01(0.001)
k = 0.00116/0.00001
= 116m⁻¹s⁻¹
<u>Rate = 116m⁻¹s⁻¹[lactose][H]⁺</u>