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3 years ago

15

If 0.100 moles of AgNO₃ react with 0.155 moles of H₂SO₄ according to this UNBALANCED equation below, what is the mass in grams o

f Ag₂SO₄ that could be formed?
AgNO₃(aq) + H₂SO₄ (aq) → Ag₂SO₄ (s) + HNO₃ (aq)

1 answer:

AlekseyPX3 years ago

4 0

Answer:

15.6g Ag2SO4

Explanation:

2AgNO3 + H2SO4 --> Ag2SO4 + 2HNO3

-2x -x

0.1-2x. 0.155-x

x=0.05 x=0.155

0.05mol Ag2SO4 x 311.78g = 15.6g Ag2SO4

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$V_2$ = volume of water = 45.0 mL

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Now put all the given values in the above formula, we get

$(0.789g/mL\times 45.0mL)\times (2.3J/g^oC)\times (T_f-9.0)^oC=-(1.0g/mL\times 45.0mL)\times 4.18J/g^oC\times (T_f-28.6)^oC$

$T_f=22.7^oC$

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