Pretty sure A is the correct answer
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Answer:
Zn(s) + 2H+(aq) => Zn²+(aq) + H2 (g)
Explanation:
The equation Zn + 2 HCI -> H₂ +zncl2 on reduction and oxidation, it results as below;
- 2H+ + 2e- => H2 ; reduction
- Zn => Zn²+ + 2e- ; oxidation
The equations above are half cell.
On combination of the above half cell reaction equations gives;
Zn(s) + 2H+(aq) => Zn²+(aq) + H2 (g).
Therefore, the half reaction equation for Zn + 2 HCI -> H₂ +zncl2 is given by;
Zn(s) + 2H+(aq) => Zn²+(aq) + H2 (g).
ΔG deg will be negative above 7.27e+3 K.
<u>Explanation:</u>
- The ΔG deg with the temperature can be found using the formula and the formula is given below
- ΔG deg = ΔH deg - T ΔS deg
- Given data, ΔH deg = 181kJ and ΔSdeg=24.9J/K
- -T ΔS deg will be always negative and ΔG deg = ΔH deg will be positive and ΔG deg will be negative at relatively high temperatures and positive at relatively low temperatures
- solving the equation and substitute ΔGdeg=0
- ΔGdeg = ΔHdeg - T ΔSdeg
- T= ΔHdeg/ΔSdeg
- T=181 kJ / 2.49e-2 kJK-1
- By simplification we get
- T=7.27 × 10^3 K.
- Therefore, Go will be negative above 7.27 × 10^3 K
- Since ΔG deg = -RT lnK, when ΔGdeg < 0, K > 1 so the reaction will have K > 1 above 7.27 × 10^3 K.
- ΔG deg will be negative above 7.27e+3 K.
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Answer:
For finding frequency, we need to first find the period of the graph.
The period of a sinusoidal graph is the time interval in which it repeats its pattern.
In the graph, we can see, after 
time, it repeats its pattern.
Hence the period of the graph is 
.
Now we need to find its frequency 
The formula for frequency is 
This is the answer
i hope you pass the assignment
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