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seraphim [82]
4 years ago
11

Which of the following is not part of Dalton's atomic theory?

Chemistry
2 answers:
Lelechka [254]4 years ago
5 0
1 is the answer atoms can be broken down into smaller pieces
Natasha_Volkova [10]4 years ago
4 0

The answer is 1. Atoms can be broken down into smaller pieces.

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4. Since water possess a partially positive and a negative end, we refer to it as?
Elanso [62]

Answer:

A polar molecule

Explanation:

8 0
2 years ago
What normally determines whether a substance is a liquid, solid, gas, or plasma?
mrs_skeptik [129]
The motion or kinetic energy of the particles determine the state of matter
4 0
3 years ago
If the solubility of a gas in water is 5.0 g/L when the pressure of the gas above the water is 2.5 atm, what is the pressure of
OLga [1]

Answer:

0.5 atm.

Explanation:

  • Henry’s law states that the amount of a gas dissolved in a  solution is directly proportional to the  pressure of the gas above the solution
  • We should use Henry’s law: <em>P = KC,</em>

where, P is the partial pressure of the  gaseous solute above the solution.

k is a constant.

C is the concentration of the  dissolved gas.

<em>At two different pressures:</em>

<em>P₁C₂ = P₂C₁,</em>

P₁ = 2.5 atm, C₁ = 5.0 g/L.

P₂ = ??? atm, C₂ = 1.0 g/L.

<em>∴ P₂ = P₁C₂/C₁</em> = (2.5 atm)(1.0 g/L)/(5.0 g/L) = <em>0.5 atm.</em>

5 0
3 years ago
Calculate the volume of concentrated 14.8 m ammonia required for the preparation of 3.1 g
Contact [7]
I think it is <span>0.823 g H2O+NH3/1 ml H2O+NH3 17.034 g NH3/1 mol 18.016 g H2O/1 mol 0.87 mol NH3/1 kg H2O</span>
8 0
3 years ago
Write the balanced equation and Ka expression for the Bronsted-Lowery acid H2AsO4 -- in water?
n200080 [17]

Answer: a. H_2AsO_4^{-}(aq)+H_2O(l)\rightarrow HAsO_4^{2-}(aq)+H_3O^+(aq)

b. K_a=\frac{[HAsO_4^{2-}]\times [H_3O^+]}{[H_2AsO_4^{-}]}

Explanation:-

According to the Bronsted-Lowry conjugate acid-base theory, an acid is defined as a substance which looses donates protons and thus forming conjugate base and a base is defined as a substance which accepts protons and thus forming conjugate acid.

The balanced chemical equation is:

H_2AsO_4^{-}(aq)+H_2O(l)\rightarrow HAsO_4^{2-}(aq)+H_3O^+(aq)

Here, H_2AsO_4^{-} is loosing a proton, thus it is considered as an acid and after losing a proton, it forms HAsO_4^{2-} which is a conjugate base.

And, H_2O is gaining a proton, thus it is considered as a base and after gaining a proton, it forms H_3O^+ which is a conjugate acid.

The dissociation constant is given by:

K_a=\frac{[HAsO_4^{2-}]\times [H_3O^+]}{[H_2AsO_4^-]}

8 0
4 years ago
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