Given :
Mass of gold ( Au ) is 212 gram.
To Find :
Atoms of gold present in 212 gram of gold.
Solution :
Molecular mass of gold is 197 gram.
So, number of moles of gold in 212 gram is :
Now, we know 1 mole of any element contains 
atoms.
So, number of atoms present in 1.076 moles are :
Hence, this is the required solution.
Answer:
Explanation:
THE QUESTION SHOULD BE
Write the equilibrium constant expression, Kc, for the following reaction: If either the numerator or denominator is 1, please enter 1 CaCO3(s).
CaCO3(s) <=> Ca2+(aq) + CO32-(aq)
Write the mathematical form of the concentration of the products, then divide it by the concentration of the reactants as follows
Kc =[Ca2+]^1 . [CO32-]^1 / [CaCO3]^1
<span>43.83g of nacl are required to </span><span>make 500.0 ml of a 1.500 m solution.</span>
My guess on that molecule is nucleus , sorry if it’s not correct
