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seraphim [82]
3 years ago
11

Which of the following is not part of Dalton's atomic theory?

Chemistry
2 answers:
Lelechka [254]3 years ago
5 0
1 is the answer atoms can be broken down into smaller pieces
Natasha_Volkova [10]3 years ago
4 0

The answer is 1. Atoms can be broken down into smaller pieces.

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The area surrounding the nucleus is called: protons electrons neutrons electron cloud
vesna_86 [32]

Answer:

eletrons

Explanation:

eletrons is not in the neuclus its around it

5 0
3 years ago
Read 2 more answers
Plz help. I just need someone to check answer. :(
My name is Ann [436]
These substances can be separated by distillation, so your answer is A.
5 0
3 years ago
Which of the following would be the best representation of input energy and then
Rom4ik [11]
A is the correct answer
4 0
2 years ago
Highest energy level for lithium​
Karo-lina-s [1.5K]

<u>Q</u><u>U</u><u>E</u><u>S</u><u>T</u><u>I</u><u>O</u><u>N</u><u> </u><u>:</u>

  • highest energy level for lithium

<u>A</u><u>N</u><u>S</u><u>W</u><u>E</u><u>R</u><u> </u><u>:</u>

  • There are 2 electrons on the first energy level and 1 electron on the second. Explain that the first energy level can only have 2 electrons so the next electron in lithium is on the next (second) level. Explain that neon has 10 protons and 10 electrons.

3 0
2 years ago
A 232-lb fullback runs the 40-yd dash at a speed of 19.8 ± 0.1 mi/h.
Neporo4naja [7]

Answer:

(a)  7.11 x 10⁻³⁷ m

(b)  1.11 x 10⁻³⁵ m

Explanation:

(a)  The de Broglie wavelength is given by the expression:

λ = h/p = h/mv

where h is plancks constant, p is momentum which is equal to mass times velocity.

We have all the data required to calculate the wavelength, but first we will have to convert the velocity to m/s, and the mass to kilograms to work in metric system.

v = 19.8 mi/h x ( 1609.34 m/s ) x ( 1 h / 3600 s ) = 8.85 m/s

m = 232 lb x ( 0.454 kg/ lb ) = 105.33 kg

λ = h/ mv = 6.626 x 10⁻³⁴ J·s / ( 105.33 kg x 8.85 m/s ) = 7.11 x 10⁻³⁷ m

(b) For this part we have to use the uncertainty principle associated with wave-matter:

ΔpΔx > = h/4π

mΔvΔx > = h/4π

Δx = h/ (4π m Δv )

Again to utilize this equation we will have to convert the uncertainty in velocity to m/s for unit consistency.

Δv = 0.1 mi/h x ( 1609.34 m/mi ) x ( 1 h/ 3600 s )  

     = 0.045 m/s

Δx = h/ (4π m Δv ) = 6.626 x 10⁻³⁴ J·s / (4π x 105.33 kg x 0.045 m/s )

     = 1.11 x 10⁻³⁵ m

This calculation shows us why we should not be talking of wavelengths associatiated with everyday macroscopic objects for we are obtaining an uncertainty of 1.11 x 10⁻³⁵ m for the position of the fullback.

5 0
3 years ago
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