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guapka [62]
3 years ago
15

A sample of solid calcium hdroxide, Ca(OH)2 is allowed to stand in water until a saturated solution is formed. A titration of 75

.00mL of this solution with 5.00 x 10-2 M HCl 36.6 mL of the acid to reach the end point
Ca(OH)2 + 2HCl ? CaCl + 2H2O
What is the molarity?
Chemistry
1 answer:
blondinia [14]3 years ago
5 0

<u>Answer:</u> The concentration of Ca(OH)_2 is 0.0122 M.

<u>Explanation:</u>

To calculate the concentration of base, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is HCl

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is Ca(OH)_2

We are given:

n_1=1\\M_1=5.00\times 10^{-2}M=0.05M\\V_1=36.6mL\\n_2=2\\M_2=?M\\V_2=75mL

Putting values in above equation, we get:

1\times 0.05\times 36.6=2\times M_2\times 75\\\\M_2=0.0122M

Hence, the concentration of Ca(OH)_2 is 0.0122 M.

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