To answer we let x be the amount of money that Sam invested during the first year.
Below are the expressions translated from the given word forms for the amount invested.
Sam:
2nd year : amount = 5x/2 - 2000
3rd year : amount = x/5 + 1000
The sum of money invested by Sam is:
x + (5x/2 - 2000) + (x/5 + 1000)
Similarly, we derive the expressions that we use for the amount that Sally invested.
Sally
1st year : amount = 3x/2 - 1000
2nd year : amount = 2x - 1500
3rd year : amount = x/4 + 1400
The total amount that Sally invested is,
total = (3x/2 - 1000) + (2x - 1500) + (x/4 + 1400)
Equating the two equations:
(x) + (5x/2 - 2000) + (x/5 + 1000) = (3x/2 - 1000) + (2x - 1500) + (x/4 + 1400)
Solving for x,
x = 2000
For Sally's investment in the third year:
amount = x/4 + 1400 = (2000/4 + 1400) = 1900
ANSWERS:
Sam's first year = $2000
Sally's third year = $1900
Answer: 12 students
Step-by-step explanation:
Let X and Y stand for the number of students in each respective class.
We know:
X/Y = 2/5, and
Y = X+24
We want to find the number of students, x, that when transferred from Y to X, will make the classes equal in size. We can express this as:
(Y-x)/(X+x) = 1
---
We can rearrange X/Y = 2/5 to:
X = 2Y/5
The use this value of X in the second equation:
Y = X+24
Y =2Y/5+24
5Y = 2Y + 120
3Y = 120
Y = 40
Since Y = X+24
40 = X + 24
X = 16
--
Now we want x, the number of students transferring from Class Y to Class X, to be a value such that X = Y:
(Y-x)=(X+x)
(40-x)=(16+x)
24 = 2x
x = 12
12 students must transfer to the more difficult, very early morning, class.
Answer:
Step-by-step explanation:
Answer:
C) the mean and median
Explanation:
Mean is affected alot, while the median is some what affected.
Answer:
its in number 2
please mark as brainliest
