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ladessa [460]
3 years ago
14

Inertia increases as an object's_______increases.

Chemistry
1 answer:
lilavasa [31]3 years ago
3 0

Answer:

<h2><em><u>MASS</u></em></h2>

Explanation:

Inertia increases as an object's <u>Mass</u> increases.

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What is the charge of Fe?
ki77a [65]
It depends on the context iorn is a transition metal so it can hold a charge from 1-8
7 0
4 years ago
13??? pls also explain how u do it
Lady_Fox [76]

Answer:

d. it has a high boiling point

Explanation:

all ionic compounds with ionic bonds have high boiling points

7 0
3 years ago
Use the rules (in order) to assign oxidation numbers to each of the elements in the compounds below.
xz_007 [3.2K]

Answer:

Explanation:

The oxidation number is an integer that represents the number of electrons that an atom receives or makes available to others when it forms a given compound.

The oxidation number is positive if the atom loses electrons, or shares them with an atom that has a tendency to accept them. And it will be negative when the atom gains electrons, or shares them with an atom that has a tendency to give them up.

Chemical compounds are electrically neutral. That is, the charge that all the atoms of a compound contribute must be globally null. That is, when having positive or negative charges in a compound, their sum must be zero.

There are some rules for determining oxidation numbers in compounds. Among them it is possible to mention:

  • Hydrogen (H) has an oxidation number +1 with nonmetals and - 1 with metals.
  • Oxygen (O) presents the oxidation number -2
  • Fluorine F has a unique oxidation state -1

Then:

  • NOF: N+(-2)+(-1)=0 → N=3 → oxidation number of  nitrogen (N) is +3, oxidation number of oxygen (O) is -2 and oxidation number of  fluorine (F) is -1.
  • ClF₅: Cl + 5*(-1)=0 → Cl= 5 → oxidation number of  chlorine (Cl) is +5 and oxidation number of  fluorine (F) is -1.
  • H₂SO₃: 2*(+1)+S+3*(-2)=0 → S=4 → oxidation number of hydrogen (H) is +1, oxidation number of oxygen (O) is -2 and oxidation number of sulfur (S) is +4.
8 0
3 years ago
The decomposition of HBr(g) into elemental species is found to have a rate constant of 4.2 ×10−3atm s−1. If 2.00 atm of HBr are
Dennis_Churaev [7]

Answer:

7,94 minutes

Explanation:

If the descomposition of HBr(gr) into elemental species have a rate constant, then this reaction belongs to a zero-order reaction kinetics, where the r<em>eaction rate does not depend on the concentration of the reactants. </em>

For the zero-order reactions, concentration-time equation can be written as follows:

                                          [A] = - Kt + [Ao]

where:

  • [A]: concentration of the reactant A at the <em>t </em>time,
  • [A]o: initial concentration of the reactant A,
  • K: rate constant,
  • t: elapsed time of the reaction

<u>To solve the problem, we just replace our data in the concentration-time equation, and we clear the value of t.</u>

Data:

K = 4.2 ×10−3atm/s,  

[A]o=[HBr]o= 2 atm,  

[A]=[HBr]=0 atm (all HBr(g) is gone)

<em>We clear the incognita :</em>

[A] = - Kt + [Ao]............. Kt =  [Ao] - [A]

                                        t  = ([Ao] - [A])/K

<em>We replace the numerical values:</em>

t = (2 atm - 0 atm)/4.2 ×10−3atm/s = 476,19 s = 7,94 minutes

So, we need 7,94 minutes to achieve complete conversion into elements ([HBr]=0).

6 0
3 years ago
S8 + 12 O2 → 8 SO3<br>How many moles of SO3 can be produced from 6 moles of O2?
MA_775_DIABLO [31]

Answer:

4 moles of SO3 will be produced from 6 moles of oxygen.

Explanation:

From the reaction given

S8 + 12 O2 ----> 8 SO3

12 moles of oxygen reacts to form 8 moles of SO3

if 6 moles of oxygen were to be used instead, it has been reduced to half of the original mole of oxygen used. Then the moles of SO3 will also be reduced to half.

6 moles of O2 will yield 4 moles of SO3

12 moles = 8 moles

6 moles = ?

? = 6 * 8 / 12

? = 48/ 12

? = 4 moles of SO3.

8 0
3 years ago
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