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4 years ago

What states can electrons exist in

1 answer:

8 0

Electrons does not have state like matter of Solid, liquid, gas or plasma states. Electrons together with other molecular and atom components makes up matter. Their characteristic and elemental inclination determines the state for which the matter will exist in.

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(15 points). The oxidation of glucose provides the principal energy source for animal cells. The reactants are glucose [C6H12O6(

miss Akunina [59]

Answer:

Check the explanation

Explanation:

The balanced reaction

C6H12O6(s) + 6O2(g) = 6CO2(g) + 6H2O(l)

Standard heat of reaction

Hrxn = 6*Hf(CO2) + 6*Hf(H2O) - 6*Hf(O2) - Hf(C6H12O6)

= 6*(-393.5) + 6*(-285.8) - 6*(0) - (-1274.4)

= - 2801.4 kJ/mol

Part b

Energy consumed by a person = 150 kJ/kg x 57 kg = 8550 kJ

Moles of glucose required = 8550 kJ / (2801.4 kJ/mol)

= 3.052 mol

Mass of glucose required = moles x molecular weight

= 3.052 mol x 180.156 g/mol

= 549.84 g

Part c

1 person requires = 3.052 mol

275 million person require = 275*10^6*3.052 = 8.39 x 10^8 mol

From the stoichiometry of the reaction

1 mol glucose produces = 6 mol CO2

8.39 x 10^8 mol glucose produces = 6*8.39*10^8

= 5.036 x 10^9 mol CO2

Mass of CO2 produced = moles x molecular weight

= 5.036 x 10^9 mol x 44 g/mol

= 2.22 x 10^11 g x 1kg/1000g

= 2.22 x 10^8 kg x 1million/10^6

= 222 million kg

5 0

4 years ago

A 0.245-L flask contains 0.467 mol co2 at 159 °c. Caculate the pressure using Van der Walls equation

AlladinOne [14]

Answer:

The right answer is "60.56 atm".

Explanation:

As we know,

Vander wall's equation is:

⇒ $(P+\frac{n^2 a}{v^2} )(v-nb)=nRT$

or,

⇒ $P=\frac{nRT}{(v-nb)}-\frac{n^2 a}{v^2}$

Here,

a = 3.59 L² atm mol⁻²

b = 0.0427 L mol⁻¹

By putting the values in the above equation, we get

⇒ $P=\frac{0.467\times 0.0821\times 432}{0.245-0.467\times 0.0427}$

$=\frac{(0.467)^2\times 3.49}{(0.245)^2}$

$=73.61-13.05$

$=60.56 \ atm$

8 0

3 years ago

While ethanol (CH3CH2OH) is produced naturally by fermentation, e.g. in beer- and wine-making, industrially it is synthesized by

Anna [14]

Answer: The number of moles of ethanol after equilibrium is reached the second time is 11. moles.

Explanation:

We are given:

Initial moles of ethene = 34 moles

Initial moles of water vapor = 15 moles

The chemical equation for the formation of ethanol follows:

$CH_2=CH_2+H_2O\rightleftharpoons CH_3CH_2OH$

Initial: 34 15

At eqllm: 34-x 15-x x

We are given:

Equilibrium moles of ethene = 24 moles

Equilibrium moles of water vapor = 5 moles

Calculating for 'x'. we get:

$34-x=24\\\\x=10$

Volume of container = 100.0 L

The expression of $K_c$ for above equation follows:

$K_c=\frac{[CH_3CH_2OH]}{[CH_2=CH_2][H_2O]}$ .......(1)

$[CH_3CH_2OH]=\frac{10}{100}=0.1M$

$[CH_2=CH_2]=\frac{24}{100}=0.24M$

$[H_2O]=\frac{5}{100}=0.05M$

Putting values in expression 1, we get:

$K_c=\frac{0.1}{0.24\times 0.05}\\\\K_c=8.3$

Now, 11 moles of ethene gas is again added and equilibrium is re-established, we get:

The chemical equation for the formation of ethanol follows:

$CH_2=CH_2+H_2O\rightleftharpoons CH_3CH_2OH$

Initial: 24+11 5 10

At eqllm: 35-x 5-x 10+x

$[CH_3CH_2OH]=\frac{10+x}{100}$

$[CH_2=CH_2]=\frac{35-x}{100}$

$[H_2O]=\frac{5-x}{100}$

Putting values of in expression 1, we get:

$8.3=\frac{\frac{(10+x)}{100}}{\frac{(35-x)}{100}\times \frac{(5-x)}{100}}\\\\8.3=\frac{(10+x)\times 100}{(35-x)\times (5-x)}\\\\x^2-52x+55=0\\\\x=50.9,1.1$

The value of 'x' cannot exceed '35', so the numerical value of x = 50.9 is neglected.

Moles of ethanol = $(10+x)=10+1.1=11.$

Hence, the number of moles of ethanol after equilibrium is reached the second time is 11. moles.

8 0

3 years ago

type of environmental factors such as the presence of a hormone that might affect an organism's phenotype is __________

rosijanka [135]

about the door is locked and I think I have a few questions about the door is locked and I think I have

Explanation:

can you tell me what the door is locked and I think I have a few questions about the door is locked and I think I have a few questions

7 0

3 years ago

Use the data in the table above to calculate an approximate ΔH∘ in kilojoules for the synthesis of hydrazine from ammonia:

dmitriy555 [2]

On the left (reactant) side you have 6 N-H bonds and 1 Cl-Cl bond
On the right (product) side you have 4 N-H bonds, 1 N-N bond and 2 H-Cl bonds 

Add up the bond energies for each side (multiplying by the number of bonds) and calculate the difference for your ΔHº

7 0

3 years ago