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3 years ago

What is the pOH in a solution that has pH = 11.39?

Chemistry

2 answers:

S_A_V [24]3 years ago

3 0

Answer:

2.61

Explanation:

pH+pOH=14, so sub in 11.39 for pOH, then subtract it over to get pH=2.61

if you have any questions, leave them in the comments and i will try to answer them, if this helped, pls give brainliest.

Aleks04 [339]3 years ago

3 0

The answer to your problem is 2.61 :)

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What is the ph of a 2.00 m hno2 solution if ka=5.00 e-6?

zysi [14]

Answer: -

2.5

Explanation: -

Initial [HNO₂] = 2.00 M

ka = 5.00 x 10 ⁻⁶

ICE table for HNO₂ =

[ $\left[\begin{array}{cccc}concentrations&HNO2&H+&NO2\\Initial&2.00&0&0\\Change&-x&+x&+x\\Equilibrium&2.00-x&x&x\end{array}\right]$

Ka = $\frac{x2}{2.00-x}$

5.00 x 10-6 = $\frac{x2}{2.00-x}$

x = 0.0032 M

pH = - log [H⁺]

= - log 0.0032

= 2.5

6 0

3 years ago

What does a circle filled in with a dark color represent in a pedigree chart?

Alina [70]

A circle or square that is not shaded indicates that a person neither expresses the trait nor is a carrier of the trait. within a family, is used. In a pedigree, a circle represents a female, and a square represents a male. A filled-in circle or square shows that the individual has the trait being studied.

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3 years ago

The molar solubilities of the following compounds (in mol/L) are:

IceJOKER [234]

Answer: The decreasing order of $K_{sp}$ is $AgSCN>AgBr>AgCN$

Explanation:

For AgBr:

The balanced equilibrium reaction for the ionization of silver bromide follows:

$AgBr\rightleftharpoons Ag^{+}+Br^-$

s s

The expression for solubility constant for this reaction will be:

$K_{sp}=[Ag^{+}][Br^-]$

We are given:

$s=7.3\times 10^{-7}mol/L$

Putting values in above equation, we get:

$K_{sp}=s\times s\\\\K_{sp}=s^2\\\\K_{sp}=(7.3\times 10{-7})^2=5.33\times 10^{-13}$

Solubility product of AgBr = $5.33\times 10^{-13}$

For AgCN:

The balanced equilibrium reaction for the ionization of silver cyanide follows:

$AgCN\rightleftharpoons Ag^{+}+CN^-$

s s

The expression for solubility constant for this reaction will be:

$K_{sp}=[Ag^{+}][CN^-]$

We are given:

$s=7.7\times 10^{-9}mol/L$

Putting values in above equation, we get:

$K_{sp}=s\times s\\\\K_{sp}=s^2\\\\K_{sp}=(7.7\times 10{-9})^2=5.93\times 10^{-17}$

Solubility product of AgCN = $5.33\times 10^{-17}$

For AgSCN:

The balanced equilibrium reaction for the ionization of silver thiocyanate follows:

$AgSCN\rightleftharpoons Ag^{+}+SCN^-$

s s

The expression for solubility constant for this reaction will be:

$K_{sp}=[Ag^{+}][SCN^-]$

We are given:

$s=1.0\times 10^{-6}mol/L$

Putting values in above equation, we get:

$K_{sp}=s\times s\\\\K_{sp}=s^2\\\\K_{sp}=(1.0\times 10{-6})^2=1.0\times 10^{-12}$

Solubility product of AgSCN = $1.0\times 10^{-12}$

The decreasing order of $K_{sp}$ follows:

$AgSCN>AgBr>AgCN$

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4 years ago

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ipn [44]

Answer:

D. THEY HAVE THE SAME NUMBER OF PROTONS AND ELECTRONS BUT DIFFERENT NUMBERS OF NEUTRONS.

Explanation:

Isotopy is the phenomenon that explains the various variants of an element having different number of neutrons but the same number of protons and electrons.

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Examples of isotopes are the hydrogen atom, chlorine element and so on.

Hydrogen has three isotopes which are hydrogen H, Deuterium and Tritium. Chlorine has two isotopes which are chlorine 35 and chlorine 37.

So the true options about isotopes is that they possess the same number of protons and electrons but different numbers of neutrins.

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Evgen [1.6K]

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