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alina1380 [7]
3 years ago
13

Write a recursive formula and an explicit formula for the following arithmetic sequence.

Mathematics
1 answer:
Serjik [45]3 years ago
3 0

Answer:

Explicit: a₁=61    aₙ=a₁ -3ₓ(n-1)

Recursive: a₁=61    aₙ=aₙ₋₁ - 3

Step-by-step explanation:

Explicit: a₁=61    aₙ=a₁ -3ₓ(n-1)

Recursive: a₁=61    aₙ=aₙ₋₁ - 3

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2,6,12,16,32,36,72 complete the number pattern​
deff fn [24]

Answer:

Next is 76, 82, 86, and 92

Step-by-step explanation:

4 0
2 years ago
Can anyone help me with #3 on this please
spayn [35]

Answer:

So I can't actually do this at the moment but I'll try to explain what to do

first find the area of the rectangle (12x16)

then, the confusing part, pretend the semicircle is a full circle and find the area and divide by 2

add the two up and put cm^{2} and that should be it

7 0
3 years ago
Abbot Tools is designing a new toolbox. The length of the toolbox will be three times its width, w, and the length of the diagon
Ilia_Sergeevich [38]

The length and width of the toolbox given the diagonal is 45 inches and 15 inches respectively.

<h3>Triangle</h3>

  • Width of the triangle = w
  • Length of the triangle = 3w
  • Diagonal = 30 inches

Hypotenuse ² = opposite ² + adjacent ²

30² = w² + (3w²)

30² = 4w²

900 = 4w²

w² = 900/4

= 225

w = √225

w = 15

Therefore,

Width of the triangle = w

= 15 inches

Length of the triangle = 3w

= 3(15)

= 45 inches

Learn more about triangles:

brainly.com/question/24382052

#SPJ1

5 0
1 year ago
Julian walked 6/10 of a mile to his friends house and another 35/100 mile to the store. He walked 1/4 of a mile back home. Julia
AveGali [126]

The statement, "Julian's sister said he walked 1/5 mile" cannot be agreed because Julian totally walked 1\frac{1}{5} \text{ or } \frac{6}{5} miles.

<u>Solution:</u>  

Given that,

  • Julian walked 6/10 of a mile to his friends house
  • Another 35/100 mile to the store
  • He walked 1/4 of a mile back home

To find total distance walked by Julian we have to add the above stated values. That is, \frac{6}{10} +\frac{35}{100} +\frac{1}{4}

Factors of 10 = 5\times2

Factors of 100 = 5\times2\times5\times2

Factors of 4 = 2\times2

Therefore, the least common factor of 10, 100 and 4 is 100. With like denominators we can operate on just the numerators,

\frac{6\times10}{10\times10} +\frac{35\times1}{100\times1} +\frac{1\times25}{4\times1}\rightarrow\frac{60+35+25}{100}\rightarrow\frac{120}{100}

\Rightarrow\frac{120}{100}\rightarrow\frac{6}{5}

Which can also be written as 1\frac{1}{5}.

So, from the above calculation it can be said that Julian walked 1\frac{1}{5} \text{ miles }.

3 0
3 years ago
Find the exact solution using common logarithms 2^5x+3= 3^2x+1
AfilCa [17]
2^{5x + 3} = 3^{2x + 1}
log_{2}(2^{5x + 3}) = log_{2}(3^{2x + 1})
(5x + 3)log_{2}(2) = (2x + 1)log_{2}(3)
5x + 3 = 1.58(2x + 1)
5x + 3 = 3.16x + 1.58
1.84x + 3 = 1.58
1.84x = -1.42
x \approx -0.77
6 0
3 years ago
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