The triarchic theory of intelligence<span> was formulated by </span>Robert J. Sternberg<span>, a prominent figure in research of human </span>intelligence<span>. The theory by itself was among the first to go against the </span>psychometric<span> approach to intelligence and take a more </span>cognitive approach<span>. The three meta components are also called triarchic components. These are the triarchic theory of human intelligence.
</span>1.
Analytical - Analytical Intelligence similar to the standard psychometric definition of intelligence e.g. as measured by Academic problem solving: analogies and puzzles, and corresponds to his earlier componential intelligence. Sternberg considers this reflects how an individual relates to his internal world.
Sternberg believes that Analytical Intelligence (Academic problem-solving skills) is based on the joint operations of metacomponents and performance components and knowledge acquisition components of intelligence
2.
Practical - Practical Intelligence: this involves the ability to grasp, understand and deal with everyday tasks. This is the Contextual aspect of intelligence and reflects how the individual relates to the external world about him or her.
<span>Sternberg states that Intelligence is: </span>"Purposive adaptation to, shaping of, and selection of real-world environments relevant to one's life" (Sternberg, 1984, p.271)
3.
Creative - Creative Intelligence: this involves insights, synthesis and the ability to react to novel situations and stimuli. This he considers the Experiential aspect of intelligence and reflects how an individual connects the internal world to external reality.
<span>Sternberg </span>considers the Creative facet to consist of the ability which allows people to think creatively and that which allows people to adjust creatively and effectively to new situations.
<span>Sternberg believes that more intelligent individuals will also move from consciously learning in a novel situation to automating the new learning so that they can attend to other tasks.</span>
I don't think that 4m has anything to do with the problem.
anyway. here.
A___________________B_______C
where A is the point that the train was released.
B is where the wheel started to stick
C is where it stopped
From A to B, v=2.5m/s, it takes 2s to go A to B so t=2
AB= v*t = 2.5 * 2 = 5m
The train comes to a stop 7.7 m from the point at which it was released so AC=7.7m
then BC= AC-AB = 7.7-5 = 2.7m
now consider BC
v^2=u^2+2as
where u is initial speed, in this case is 2.5m/s
v is final speed, train stop at C so final speed=0, so v=0
a is acceleration
s is displacement, which is BC=2.7m
substitute all the number into equation, we have
0^2 = 2.5^2 + 2*a*2.7
0 = 6.25 + 5.4a
a = -6.25/5.4 = -1.157
so acceleration is -1.157m/(s^2)
Answer:
B
Explanation:
the graph shows the line going up (accelerating) and it isn't curving like d so it doesn't stop accelerating
Hope this helps :)
Te direction of the magnetic force for the velocity of the proton in the
-ve y direction will be +ve z direction.
As we know that the right-hand rule is based on the relation of magnetic fields and the forces that they exert on moving charges.When a charged particle moves under a magnetic field, it exerts a force on the particle, which is not in the same direction but different than the direction of the magnetic field.Under the right-hand rule, if we point our pointer finger in the direction of the charged particle is moving and the middle finger is representing the direction of the magnetic field then our thumb depicts the direction of the magnetic force which is exerted on the charged particle.
So, we are given that the direction of the velocity of the proton is in the negative y direction and the direction of the magnetic field is in the positive x direction, so the magnetic force is acting in the positive z direction.
To know more about the right-hand rule refer to the link brainly.com/question/9750730?referrer=searchResults.
#SPJ4
Answer:
24.57 revolutions
Explanation:
(a) If they do not slip on the pavement, then the angular acceleration is
(b) We can use the following equation of motion to find out the angle traveled by the wheel before coming to rest:
where v = 0 m/s is the final angular velocity of the wheel when it stops, 
= 95rad/s is the initial angular velocity of the wheel, 
is the deceleration of the wheel, and 
is the angle swept in rad, which we care looking for:
As each revolution equals to 2π, the total revolution it makes before stop is
154.375 / 2π = 24.57 revolutions
