Answer:
Explanation:
force of friction = μ mg
= .3 x 62 x 9.8
= 182.28 N
Work done by friction = 182.28 x 4.8
= 874.94 J
Energy loss by skier = 874.94 J
Kinetic energy after he passes the rough patch
= 1/2 x 62 x 6.8² - 874.94
= 1433.44 - 874.94
= 558.5 J
Velocity after crossing the patch v
1/2 x 62 x v² = 558.5
v² = 18
v = 4.2426 m /s
velocity at the bottom
v² = u² + 2gh
= 18 + 2 x 9.8 x 2.5
= 67
v = 8.18 m /s
b ) internal energy generated =
Work done by friction . = 874.94 J
Wood frogs have this adaptation where they accumulate urea in their bodies and convert their liver glycogen to glucose to act as cryoprotectants. This prevents the formation of ice crystals in their bodies that could cause damage cells during freezing in winter.
Answer:
Surface charge density will be ![3.812\times 10^{-6}C/m^2](https://tex.z-dn.net/?f=3.812%5Ctimes%2010%5E%7B-6%7DC%2Fm%5E2)
Explanation:
We have given speed of the belt v = 43 m/sec
Width of the belt w = 61 cm
We know that charge is equal to Q = It, here Is current and t is time
And time is equal to
, here L is distance and v is speed
Putting the value of t in charge equation
![Q=i\times \frac{L}{v}=\frac{iL}{v}](https://tex.z-dn.net/?f=Q%3Di%5Ctimes%20%5Cfrac%7BL%7D%7Bv%7D%3D%5Cfrac%7BiL%7D%7Bv%7D)
Surface charge density is equal to ![\sigma =\frac{Q}{A}=\frac{iL}{vA}](https://tex.z-dn.net/?f=%5Csigma%20%3D%5Cfrac%7BQ%7D%7BA%7D%3D%5Cfrac%7BiL%7D%7BvA%7D)
We know that width is equal to ![w=\frac{A}{L}](https://tex.z-dn.net/?f=w%3D%5Cfrac%7BA%7D%7BL%7D)
So ![\sigma =\frac{i}{vw}=\frac{100\times 10^{-6}}{43\times 0.61}=3.812\times 10^{-6}C/m^2](https://tex.z-dn.net/?f=%5Csigma%20%3D%5Cfrac%7Bi%7D%7Bvw%7D%3D%5Cfrac%7B100%5Ctimes%2010%5E%7B-6%7D%7D%7B43%5Ctimes%200.61%7D%3D3.812%5Ctimes%2010%5E%7B-6%7DC%2Fm%5E2)