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kondor19780726 [428]
3 years ago
10

Construct c = a + b by drawing and calculating the direction and magnitude of c. The direction should be

Physics
1 answer:
Black_prince [1.1K]3 years ago
6 0

the method of the coordinates we can find the vector sum of the two vectors given, therefore the answer is:

              c = 10.15

              a = 70.4º

measured counterclockwise from the positive side of the x-axis

given parameters

  • vectors a and b

to find

  • the vector adds

The sum of vectors must take into account finding both the magnitude of the vector that is a scalar and its direction.

One of the best methods to perform vector addition is to add their component and then find the resulting vector.

Let's use trigonometry to find the components of vectors a and b, we take the data from the diagram.

Vector a

magnitude m_a = 8.0

angle  θ= 45º   in the second quadrant

           cos 45 = x_a / m_a

           sin 45 = y_a / m_a

           x_a = m_a cos 45

           y_a = m_a sin 45

           x_a = 8.0 cos 45 = 5.657

           y_a = 8.0 sin 45 = 5.657

as we are in the second quadrant, see diagram

          x_a = - 5,657

          y_a = 5,627

     

Vactor b

magnitude m_b = 4.5

angle  θ = 60º   in the first quadrant

             cos 60 = x_b / m_b

             sin 60 = y_b / m_b

             x_b = m_b cos 60

             y_b = m_b sin 60

             x_b = 4.5 cos 60 = 2.25

             y_b = 4.5 sin 60 = 3.897

Having the components encode the components of the resulting vector

             cₓ = x_a + x_b

             c_y = y_a + y_b

             cₓ = - 5.657 + 2.25 = 3.407

             c_y = 5,657 + 3,897 = 9,554

With these values ​​we can find the modulus of the vector using the Pythagoras Theorem

             c = \sqrt{c_x^2 + c_y^2}

             c = \sqrt{3.407^2 + 9.554^2}

             c = 10.14

for the angle we must use the trigonometry relations

             tan  θ = \frac{c_y}{c_x}    

              θ = tan⁻¹ \frac{c_y}{c_x}

              θ = tan⁻¹ \frac{9.554}{3.407}

              θ = 70.4º

In conclusion with the method of coordinates we can find the resulting vector

             magnitud  c= 10.15

             angle  θ = 70.4º

measured counterclockwise from the positive side of the x axis

learn more about vector addition here:

brainly.com/question/15074838

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aleksklad [387]

Answer:

The new position is 0.1865 m

Explanation:

As the context of the data is not available, thus following data is utilized from the question as attached above

x_relax=0.32 m

x_stiff=0.13 m

spring stiffness k=9 N/m

mass of block =0.073 kg

t=0.07 s

Velocity of the block is to be estimated thus

Force due to compression in spring is given as

F_s=k Δx

F_s=9(0.32-0.13)

F_s=1.71 N

Force on the block is given as

F_m=mg

F_m=0.073 x 9.8

F_m=0.71 N

Net Force

F=F_s-F_m

F=1.71-0.71 N

F=1 N

As Ft=Δp

So

Δp=1x0.07=0.07 kgm/s

Δp=p_final-p_initial

0.07=p_final-0

p_final=0.07 kgm/s

p_final=m*v_f

v_f=(p_final)/(m)

v_f=0.07/0.073

v_f=0.95 m/s

So now the velocity of the block is 0.95 m/s

time is 0.07 s

y_new=y_initial+y_travel

y_new=0.12+(0.95 x 0.07)

y_new=0.12+0.065

y_new=0.1865 m

So the new position is 0.1865 m

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Determine the mass of an object if it's moving at 5 m/s and has a momentum of 50 kg*m/s
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I think the mass is 250 kg
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7) If the mass of an object is 694 g, find the mass of rider 1 if rider 2 = 600g rider 3 = 90 (Subtract the smaller numbers from
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The mass of the rider 1 is 4 g.

<h3>The use of a rider in mass measurement</h3>

Rider is a metallic wire piece which is of certain mass and can be bent . It can move the beam of the Paul Bunge Balance.

The riders are the sliding pointers positioned on top of the beams to show the pan and beam weight in grams.

<h3>Mass of the rider 1</h3>

The mass of the rider 1 is obtained by subtracting mass of riders as show below.

mass of rider 1 = mass of object - (mass of rider 2 + mass of rider 3)

mass of rider 1 = 694 g  - (600 g + 90 g)

mass of rider 1 = 694 g - 690 g

mass of rider 1 = 4 g

Thus, the mass of the rider 1 is 4 g.

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2 years ago
When you drop a 0.43 kg apple, Earth exerts
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The magnitude of the Earth's acceleration is 7.0\cdot 10^{-25} m/s^2

Explanation:

First of all, we start by calculating the magnitude of the force exerted by the apple on the Earth. According to Newton's third law, this is equal to the force exerted by the Earth on the apple, which is the weight of the apple, given by:

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g=9.8 m/s^2 is the acceleration of gravity

Substituting,

F=(0.43)(9.8)=4.2 N

Now we can find the Earth's acceleration by applying Newton's second law:

F=Ma

where:

F = 4.2 N is the net force exerted by the apple on the Earth

M=5.98\cdot 10^{24} kg is the mass of the Earth

a is the Earth's acceleration

And solving for a, we find:

a=\frac{F}{M}=\frac{4.2}{5.98\cdot 10^{24}}=7.0\cdot 10^{-25} m/s^2

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