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Nikitich [7]
3 years ago
6

How is resonance used in musical instruments

Physics
2 answers:
sweet-ann [11.9K]3 years ago
8 0
Musical instruments use resonance to amplify the sound and make the sounds louder
S_A_V [24]3 years ago
4 0

Explanation:

Resonance is the vibration or oscilation at certain frequency that is produce by an object, in this case, a musical instrument. Resonance depends on the intrument's shape, material, tension, etc. and is used to produce harmonic frequencies that give instruments their characteric sounds.

I hope you find this information useful and interesting! Good luck!

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<span>Match the basic components of a nuclear reactor with their descriptions. 1. slows down neutrons moderator - This is the substance that slows down fast neutrons and makes them slow neutrons which are easier to capture by the atomic nuclei so that the fission reaction can continue. 2. absorb emitted neutrons control rods - These are rods made up of a substance that easily absorbs neutrons. Their purpose is to slow down or shut down the reaction. 3. mass of unstable atoms nuclear fuel - The entire point of a nuclear reactor is the capture the energy released by the fission of unstable atoms. So this mass of unstable atoms is the fuel for the nuclear reactor. 4. concrete and lead enclosure shield - This is the enclosure that prevents radiation from escaping into the general environment. 5. energy transfer medium coolant - Since the purpose of a nuclear reactor is to generate usable energy, the coolant extracts heat from the fissioning core and that heat is generally used to boil water which in turn is used to operate turbines that power electrical generators.</span>
3 0
3 years ago
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Consider a model of a hydrogen atom in which an electron is in a circular orbit of radius r = 5.92×10−11 m around a stationary p
DaniilM [7]

Answer:

2.068 x 10^6 m / s

Explanation:

radius, r = 5.92 x 10^-11 m

mass of electron, m = 9.1 x 10^-31 kg

charge of electron, q = 1.6 x 10^-19 C

As the electron is revolving in a circular path, it experiences a centripetal force which is balanced by the electrostatic force between the electron and the nucleus.

centripetal force = \frac{mv^{2}}{r}

Electrostatic force = \frac{kq^{2}}{r^{2}}

where, k be the Coulombic constant, k = 9 x 10^9 Nm^2 / C^2

So, balancing both the forces we get

\frac{kq^{2}}{r^{2}}=\frac{mv^{2}}{r}

v=\sqrt{\frac{kq^{2}}{mr}}

v=\sqrt{\frac{9\times 10^{9}\times1.6\times 10^{-19}\times 1.6\times 10^{-19}}{9.1\times 10^{-31}\times 5.92\times10^{-11}}}

v = 2.068 x 10^6 m / s

Thus, the speed of the electron is give by  2.068 x 10^6 m / s.

6 0
3 years ago
Which of the following is not a constant or control for this experiment?
SCORPION-xisa [38]
D.the amount of time in sun
8 0
3 years ago
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A negative charge of - 8.0 x 10^-6 C exerts an attractive force of 12 N on a second charge that is
Umnica [9.8K]

Answer:

<h2>Magnitude of the second charge is -4.17*10^{-7}C</h2>

Explanation:

According to columbs law;

F = kq1q2/r^{2}

F is the attractive or repulsive force between the charges = 12N

q1 and q2 are the charges

let q1 = - 8.0 x 10^-6 C

q2=?

r is the distance between the charges = 0.050m

k is the coulumbs constant =9*10⁹ kg⋅m³⋅s⁻⁴⋅A⁻²

On substituting the given values

12 = 9*10⁹*( - 8.0 x 10^-6)q2/0.050²

Cross multiplying

0.03=9*10^{9}*  -8.0*10^{-6} q2\\0.03 = -72*10^{3} q2\\q2 = \frac{0.03}{ -72*10^{3}} \\q2 = -4.17*10^{-7}C

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3 years ago
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What features form where two continental plate come together
ExtremeBDS [4]
Ridges, mountains, and volcanoes!

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