Answer:
W = 18.88 J
Explanation:
Given that,
Constant force, F = 11.8 N (in +x direction)
Mass of an object, m = 4.7 kg
The object moves from the origin to the point (1.6i – 4.6j) m
We need to find the work is done by the given force during this displacement. The work done by an object is given by the formula as follows :

So, the work done by the given force is 18.88 J.
The string moves to the right, as it restores its original position with the median plane of the bow. As a result, the string "pulls" on the arrow with a force F2. 2. The tip of the arrow T moves slightly to the left.
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Answer:
The attached diagram explains the system,
Sum of Fy = 0
N=9.81
N - mgCos60 = 0
F= ukN= (0.53)(9.81) =
F= 5.12 N
So
F.d= 1/2(mv.v) - mgdsin60
-5.12*0.5 = 0.5*v^2 - 2*(9.81)*(0.5*sin60)
(a) v = 2.436 m/s
For deflection
-F.x = 1/2(mv.v) - mgxsin60 + 1/2 (k*x*x)
by solving for with values of v, m, g, F, k
800x^2 - 11.87 x - 5.938 = 0
by solving the quadratic equation
x = 0.093, -0.079
(b) x = 0.093 m
correct Answer is 0.093m
Explanation:
Answer:
false, because a phase change occurs physical changes when matter changes its energy state.