Answer:
113.58 m
Explanation:
Range = Maximum Height
tan θ = 4
θ = 76 degree
Let u be the velocity of projection
K = 1/2 x m x u^2
1150 = 0.5 x 0.97 x u^2
u = 48.7 m/s
Range = [tex]\frac{u^{2}Sin2\theta }{g}
R = (48.7 x 48.7 x 2 x Sin 76 x Cos 76) / 9.8 = 113.58 m
Answer:
This question is incomplete
Explanation:
The question is incomplete. However, to determine the time (in seconds) it took a worker to hit the ground from an elevated point. The speed the worker was coming with to the ground and the distance between the elevated point and the ground will have to be considered. Thus the formula to be used here will be
Speed (in meter per second) = distance (in meters) ÷ time (in seconds)
time (in seconds) = distance (in meters) ÷ speed (in meter per seconds)
Answer:
C. Dark Matter
Explanation:
Dark matter is estimated to make up 90 percent of the mass of the galaxy.
The dark matter (as astronomers have come to call the invisible material) extends to a distance of at least 200,000 light-years from the center of the Galaxy.
