Answer:
E = q V B describes the electric field induced
E Proportional to V B
while the magnet is pushed into the coil the induced field (B) will increase (consider 1 turn of the coil)
If V is constant the E-field will increase due to increasing B and the galvanometer will deflect accordingly
When V drops to zero the deflection must again be zero
So one would see a blip due to the deflection of the galvanometer
Note that as V increases the galvanometer will deflect one way and then as V drops to zero the deflection will be opposite (drop to zero when V is zero)
B always increases to a constant value because of the properties of the magnet.
Answer:
0.000136kg/m3
Explanation:
13.6 / 1000 = 0.0136kg/cm3
0.0136 / 100 = 0.000136kg/m3
I think the answer is 2.
Hope this helps
The capacitance of two square parallel plates will be 1.777 farads.
<h3>What is the capacitance of two parallel plates?</h3>
The body's capacity to hold electric charge is constrained by capacitance. There is a capacitance for each capacitor. Two metallic sheets of area A, spaced by d, make up the standard parallel-plate capacitor.
The parallel plate capacitor formula is given by:
C = ε Ad
Two square parallel plates 6.7 cm on a side are separated by 1.8 mm of paraffin. The dielectric constant of paraffin is 2.2. Then the capacitance of two square parallel plates will be given as,
C = ε Ad
C = 2.2 x 0.67 x 0.67 x 1.8
C = 1.777 farad
Two parallel square plates will have a capacitance of 1.777 farads.
More about the capacitance of two parallel plates link is given below.
brainly.com/question/12733413
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