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3 years ago

15

one small pitcher and one large pitcher can hold 12 cups of water. if the large pitcher is twice the size of the small pitcher,

how much does the small pitcher hold?

2 answers:

V125BC [204]3 years ago

8 0

The small pitcher holds 4 cups not 3 because of the small holds 4 and the large holds 8 (8+4=12) and 8 is twice the size of 4 (4*2=8)

netineya [11]3 years ago

7 0

THe small pitcher holds 3 cups

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Evaluate Expressions

iren [92.7K]

5(7)-7
35-7
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3 years ago

WILL GIVE BRAINLIEST 15 POINTS!!! Consider the following pair of equations:

ale4655 [162]

The two lines will intersect at the point (2, 3).

We can find this by setting the two equations equal to eachother, as the point at which they intersect is the point where they share the same x and y value. First, we have to get both equations in the form y = mx + c, so:
-x - y = -5
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y = -x + 5

Now we can set -x + 5 equal to x + 1 and solve to find the x coordinate:

-x + 5 = x + 1
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So the final answer is (2, 3).

I hope this helps!

-x + 5 = x + 1

5 0

3 years ago

A rectangle or patio has a length of 12 1/2 feet and an area of 103 1/8 feet. What is the width of the patio?

AfilCa [17]

The width of the patio is 8 7/25 feet ( I hope I got that right )

7 0

3 years ago

The ratio of the height of two similar pyramids is 4:7. The volume of the smaller pyramid is 1,331cm, to the nearest whole numbe

IRISSAK [1]

Answer:

The volume of the larger pyramid is equal to $7,133\ cm^{3}$

Step-by-step explanation:

step 1

Find the scale factor

we know that

If two figures are similar, then the ratio of its corresponding sides is equal to the scale factor

Let

z----> the scale factor

In this problem, the ratio of the height is equal to the scale factor

$z=\frac{4}{7}$

step 2

Find the volume of the larger pyramid

we know that

If two figures are similar, then the ratio of its volumes is equal to the scale factor elevated to the cube

Let

z----> the scale factor

x----> volume of the smaller pyramid

y----> volume of the larger pyramid

$z^{3}=\frac{x}{y}$

we have

$z=\frac{4}{7}$

$x=1,331\ cm^{3}$

substitute

$(\frac{4}{7})^{3}=\frac{1,331}{y}\\ \\(\frac{64}{343})=\frac{1,331}{y}\\ \\y=343*1,331/64\\ \\y=7,133\ cm^{3}$

8 0

3 years ago

Allen needs to prepare a compound for the patient to pick up tomorrow. He needs to mix of drug A, with of drug B and of drug C.

Phoenix [80]

Answer:

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Add the drug combinations together

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3 years ago