Which statement describes Rutherford model of an atom

Can you name three dangers to the environment that some people use everyday in their homes without realizing it?

konstantin123 [22]

Answer:

1 COSMETICS WITH MICROBEADS

2 COFFEE CAPSULES

3 WET WIPES

Explanation:

1.Plastic microbeads began to be introduced in cosmetics, toiletries and cleaning products in the 1970s, but it wasn’t until the 1990s that brands began to incorporate them in a massive way. Toothpastes, creams, lotions, shampoos and detergents began to include microbeads as the great innovation of the time for achieving an abrasive effect, replacing the nature-based materials in use until then.

2 Capsule coffee machines have revolutionized the breakfasts of millions of people, offering a convenient and practical option for preparing an espresso or latte with the same quality one finds in a café. Data from 2017 indicate that 29% of US coffee consumers use these machines, a figure that continues to grow.

3They started off being an invaluable aid for fathers and mothers when facing the messy moment of their baby’s diaper change, but soon they began to be reinvented as deodorants, cleansers, disinfectants and hand soap substitutes, and even as toilet paper for adults. Wet wipes have become a common item in many homes, but with a dramatic consequence: they help to create fatbergs, immense accumulations that block the sewerage networks and that are composed of 93% non-degradable wipes, together with fat, condoms and other similar items thrown into the toilet.

3 0

3 years ago

Find the value of currents through each branch

Irina-Kira [14]

Answer:

the branch currents are as follows:

top left: I2 = 0.625 A

middle left: I1 = 2.500 A

bottom left: I1-I2 = 1.875 A

top center: I2+I3 = 2.500 A

bottom center: I2+I3-I1 = 0 A

right: I3 = 1.875 A

Explanation:

You can write the KVL equations:

Top left loop:

I2(4) +(I2 +I3)(2) +I1(1) = 10

Bottom left loop:

(I1-I2)(4) +(I1-I2-I3)(2) +I1(1) = 10

Right loop:

(I2+I3)(2) +(I2+I3-I1)(2) = 5

In matrix form, the equations are ...

$\left[\begin{array}{ccc}1&6&2\\7&-6&-2\\-2&4&4\end{array}\right]\cdot\left[\begin{array}{c}I_1\\I_2\\I_3\end{array}\right] =\left[\begin{array}{c}10\\10\\5\end{array}\right]$

These equations have the solution ...

$\left[\begin{array}{c}I_1\\I_2\\I_3\end{array}\right] =\left[\begin{array}{c}2.500\\0.625\\1.875\end{array}\right]$

This means the branch currents are as follows:

top left: I2 = 0.625 A

middle left: I1 = 2.500 A

bottom left: I1-I2 = 1.875 A

top center: I2+I3 = 2.500 A

bottom center: I2+I3-I1 = 0 A

right: I3 = 1.875 A

_____

This can be worked almost in your head by using the superposition theorem. When the 5V source is shorted, the 10V source is supplying (I1) to a circuit that is the 4 Ω and 2 Ω resistors in parallel with their counterparts, and that 2+1 Ω combination in series with 1 Ω for a total of a 4Ω load on the 10 V source. That is, I1 due to the 10V source is 2.5 A, and it is nominally split in half through the upper and lower branches of the circuit. There is no current flowing through the (shorted) 5 V source branch.

When the 10V source is shorted, the 5V source is supplying a 4 +4 Ω branch in parallel with a 2 +2 Ω branch, a total load of 8/3 Ω. This makes the current from that source (I3) be 5/(8/3) = 15/8 = 1.875 A. There is zero current from this source through the 1 Ω resistor.

Nominally, the current from the 5V source splits 2/3 through the 2 Ω branch and 1/3 through the 4 Ω branch.

Using superposition, I2 = I1/2 -I3/3 = (2.5 A/2) -(1/3)(15/8 A) = 0.625 A. This is the same answer as above, without any matrix math.

(I1, I2, I3) = (2.5 A, 0.625 A, 1.875 A)

__

It helps to be familiar with the formulas for resistors in series and parallel.

8 0

3 years ago

what is the acceleration produced by the resultant force acting on an object if the coefficient of friction acting between the b

LenKa [72]

The acceleration of the block is $-0.98 m/s^2$

Explanation:

The expression for the force of friction acting on the block is (assuming the surface is horizontal and flat):

$F_f = -\mu mg$

where

$\mu$ is the coefficient of friction

m is the mass of the block

g is the acceleration of gravity

and where the negative sign means the direction of the force is opposite to that of the motion of the block

If this is the only force acting on the object, then this is also the resultant force, so we can rewrite Newton's second law as:

$F=ma\\-\mu mg = ma$

where

a is the acceleration of the block

Re-arranging the equation,

$a=-\mu g$

And so this is the expression for the acceleration of the block acted upon the force of friction.

In this problem, we have:

$\mu=0.1$

$g=9.8 m/s^2$

Solving,

$a=-(0.1)(9.8)=-0.98 m/s^2$

Learn more about friction:

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#LearnwithBrainly

5 0

4 years ago

For the winter, a duck flies 10.0 m/s due south against a gust of wind with a velocity of 2.5 m/s. What is the resultant velocit

maria [59]

Answer:

c. 7.5 m/s south

Explanation:

<u>Given the following data;</u>

Velocity of duck = 10m/s due South

Velocity of wind = 2.5m/s

To find the resultant velocity;

Since we know that the duck is flying against a gust of wind, we would have to subtract the velocity of the gust of wind from that of the duck.

This ultimately implies that, the gust of wind (headwind) would decrease the resulting velocity of the duck because it approaches the duck from the front.

Resultant velocity, /V/ = 10 - 2.5

Resultant velocity, /V/ = 7.5m/s South.

<em>Therefore, the resultant velocity of the duck is 7.5m/s south. </em>

6 0

3 years ago

Some metals have a molecular structure that makes them good conductors. Explain how understanding this relationship can help eng

erastova [34]

Answer:

Explained below.

Explanation:

Conductors can be defined as materials that permit electricity to flow through them easily.

Now, metals have a molecular structure that makes them good conductors because electrons in the atoms of these conductors tend to move freely from one atom to the other. So a majority of metals make good conductors because these metals tend to hold their electrons loosely. In short, it can help engineers make powerful batteries because then it means that they are capable of giving much more electrical energy since nowadays, advanced batteries make use of ion charges for the batteries.

7 0

3 years ago